Farm Tour Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 18150   Accepted: 7023 Description When FJ's friends visit him on the farm, he likes to show them around. His farm comprises N (1 <= N <= 1000) fields numbered 1..N, the first of…

描述 When FJ's friends visit him on the farm, he likes to show them around. His farm comprises N (1 <= N <= 1000) fields numbered 1..N, the first of which contains his house and the Nth of which contains the big barn. A total M (1 <= M <= 10000)…

题目链接:http://poj.org/problem?id=2135 Farm Tour Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 17672   Accepted: 6851 Description When FJ's friends visit him on the farm, he likes to show them around. His farm comprises N (1 <= N <= 1000…

Farm Tour Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 17230   Accepted: 6647 Description When FJ's friends visit him on the farm, he likes to show them around. His farm comprises N (1 <= N <= 1000) fields numbered 1..N, the first of…

题目链接 题意:无向图有N(N <= 1000)个节点,M(M <= 10000)条边:从节点1走到节点N再从N走回来,图中不能走同一条边,且图中可能出现重边,问最短距离之和为多少? 思路:很经典的构图(看题解的);每条原图中的边赋予cap为1,表示只走一次.超级源点s和汇点t分别和起点终点连边,cap为2,这里cap为2就直接限制了只能有两次最大流:同时最大流中以权值限制得到的就是最小费用:很注意的一点就是此题为无向图带权值,建图时每条有向边建成两条即总边数为4*M.由于spfa找最短路是有…

题意: 有n个点和m条边,让你从1出发到n再从n回到1,不要求所有点都要经过,但是每条边只能走一次.边是无向边. 问最短的行走距离多少. 一开始看这题还没搞费用流,后来搞了搞再回来看,想了想建图不是很难,因为要保证每条边只能走一次,那么我们把边拆为两个点,一个起点和终点,容量是1,权重是这条路的长度.然后两个端点分别向起点连接容量是1权重是0的边,终点分别向两个端点连容量是1权重是0的边,从源点到1连容量为2权重为0的边,从n到汇点连容量为2权重为0的边. #include<stdio.h>…

原题 费用流板子题. 费用流与最大流的区别就是把bfs改为spfa,dfs时把按deep搜索改成按最短路搜索即可 #include<cstdio> #include<queue> #include<cstring> #define N 20020 using namespace std; int n,m,src, des, head[N],dis[N],cur[N],ans,cnt=2,s,t, ANS; queue <int> q; bool vis[N]…

图论算法-最小费用最大流模板[EK;Dinic] EK模板 const int inf=1000000000; int n,m,s,t; struct node{int v,w,c;}; vector<node> map[10010]; int flow[10010][10010]; bool inq[10010]; int d[10010]; int pre[10010],pref[10010]; int minc,maxf; int main() { cin>>n>>…

Matrix Again Time Limit: 5000/2000 MS (Java/Others)    Memory Limit: 102400/102400 K (Java/Others)Total Submission(s): 4255    Accepted Submission(s): 1233 Problem Description Starvae very like play a number game in the n*n Matrix. A positive integer…

https://www.luogu.org/problem/P3381 题目描述 如题,给出一个网络图,以及其源点和汇点,每条边已知其最大流量和单位流量费用,求出其网络最大流和在最大流情况下的最小费用. 输入格式 第一行包含四个正整数N.M.S.T,分别表示点的个数.有向边的个数.源点序号.汇点序号. 接下来M行每行包含四个正整数ui.vi.wi.fi,表示第i条有向边从ui出发,到达vi,边权为wi(即该边最大流量为wi),单位流量的费用为fi. 输出格式 一行,包含两个整数,依次为最大流量和…