for the backtracking part, thanks to the video of stanford cs106b lecture 10 by Julie Zelenski for the nice explanation of recursion and backtracking, highly recommended. in hdu 2553 cout N-Queens solutions problem, dfs is used. // please ignore, bel…
backtracking最基础的问题是Subsets,即给定一个数组,要求返回其所有子集. Given a set of distinct integers, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. backtracking的原理是深度优先遍历…
Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. Example: Input: [1,2,2] Output: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 这个题目思路…
Given a set of distinct integers, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. Example: Input: nums = [1,2,3] Output: [ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [] ] …
根据issac3 用Java总结了backtracking template, 我用他的方法改成了Python. 以下为template. def backtrack(ans, temp, nums, start): # 可能有start, 也可能没有 if len(temp) == len(nums): ans.append(temp) else: for i in range(start, len(nums)): if nums[i] not in temp: backtrack(ans,…