ZOJ3965 给定一颗二叉树的两种DFS序列 输出一种可能的二叉树的结构. 考察树的递归性质,不要想的太复杂. 当前节点在两个串中后面的节点假如不同则能确认两个子树,如果相同则把下个点作当前点的一个儿子.如果子树中还有未连根的点则接到当前点下.son数组表示每个点的子树有多少个点.pos数组记录每个数在每个序列中的位置.dfs中p1,p2指向同一个数 lim1,lim2表示当前点子树可能最大的子树范围. #include<iostream> #include<cstdio> #i…

Binary Tree Restoring 思路: 递归 比较a序列和b序列中表示同一个子树的一段区间,不断递归 代码: #include<bits/stdc++.h> using namespace std; #define LL long long #define pb push_back #define mem(a,b) memset(a,b,sizeof(a)) ; int a[N],b[N],par[N],posa[N],posb[N],sum[N],n; void dfs(int…

Binary Tree Restoring Time Limit: 1 Second      Memory Limit: 65536 KB      Special Judge Given two depth-first-search (DFS) sequences of a binary tree, can you find a binary tree which satisfies both of the DFS sequences? Recall that a binary tree i…

地址:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3965 题目: iven two depth-first-search (DFS) sequences of a binary tree, can you find a binary tree which satisfies both of the DFS sequences? Recall that a binary tree is a tree in which…

二叉树(Binary Tree)是最简单的树形数据结构,然而却十分精妙.其衍生出各种算法,以致于占据了数据结构的半壁江山.STL中大名顶顶的关联容器--集合(set).映射(map)便是使用二叉树实现.由于篇幅有限,此处仅作一般介绍(如果想要完全了解二叉树以及其衍生出的各种算法,恐怕要写8~10篇). 1)二叉树(Binary Tree) 顾名思义,就是一个节点分出两个节点,称其为左右子节点:每个子节点又可以分出两个子节点,这样递归分叉,其形状很像一颗倒着的树.二叉树限制了每个节点最多有两个子节…

题目链接:Balanced Binary Tree | LeetCode OJ Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more tha…

Sept. 13, 2015 Spent more than a few hours to work on the leetcode problem, and my favorite blogs about this problems: 1. http://siddontang.gitbooks.io/leetcode-solution/content/tree/construct_binary_tree.html 2.http://blog.csdn.net/linhuanmars/artic…

Given a binary tree, find all leaves and then remove those leaves. Then repeat the previous steps until the tree is empty. Example: Given binary tree 1 / \ 2 3 / \ 4 5 Returns [4, 5, 3], [2], [1]. Explanation: 1. Remove the leaves [4, 5, 3] from the…

One way to serialize a binary tree is to use pre-oder traversal. When we encounter a non-null node, we record the node's value. If it is a null node, we record using a sentinel value such as #. _9_ / \ 3 2 / \ / \ 4 1 # 6 / \ / \ / \ # # # # # # For…

Given a binary tree, return the vertical order traversal of its nodes' values. (ie, from top to bottom, column by column). If two nodes are in the same row and column, the order should be from left to right. Examples: Given binary tree [3,9,20,null,n…