CodeForcesGym 100753B Bounty Hunter II】的更多相关文章

Bounty Hunter II Time Limit: 5000ms Memory Limit: 262144KB This problem will be judged on CodeForcesGym. Original ID: 100753B64-bit integer IO format: %I64d      Java class name: (Any) 解题:最小路径覆盖 #include <bits/stdc++.h> using namespace std; ; vector…
关键在建图 题解:http://www.cnblogs.com/crackpotisback/p/4856159.html 学习:http://www.cnblogs.com/jackiesteed/articles/2043934.html…
出处:https://www.hackerone.com/blog/become-a-successful-bug-bounty-hunter 如果你梦想成为赏金猎人,你的梦想就会成真 - 不要把你的名字变成“狗”或者在Mos Eisley酒吧面对Han Solo. 成为一个bug赏金猎人:一个有钱寻找软件和网站漏洞的黑客. 任何具有计算机技能和高度好奇心的人都可以成为漏洞的成功者. 你开始时可以年轻或年老. 主要要求是你需要不断学习. 此外,如果你有一个伙伴分享想法,那么学习会更有趣. 以下是…
Time Limit:5000MS     Memory Limit:131072KB     64bit IO Format:%lld & %llu Submit Status id=134850" target="_blank"> Practice id=134850" target="_blank"> CSU 1527 Description Input Output Sample Input 2 5 0 1 1 2 2…
Divisions David is a young boy and he loves numbers. Recently he learned how to divide two numbers.David divides the whole day. He is happy if the result of the division is an integer, but he is not very amused if this is not the case. After quite a…
$$2015\ German\ Collegiate\ Programming\ Contest\ (GCPC 15) + POI 10-T3$$ \(A.\ Journey\ to\ Greece\) 状压DP,TSP,先考虑找出这些关键点之间的最短路,然后就是旅行商问题,其中可以用一次\(taxi\),考虑\(dp\)状态为\(f[i][msk][tag]\),表示当前所在位置为\(i\)点,已经经过的节点集合为\(msk\),是否用过\(taxi\)的情况下,所化的最小时间,最后再从走遍了…
https://github.com/ngalongc/bug-bounty-reference/blob/master/README.md#remote-code-execution Bug Bounty Reference 根据Bug归类的Bug赏金记录列表,灵感来自https://github.com/djadmin/awesome-bug-bounty 介绍 我几个月来一直在阅读Bug Bounty的文章,我发现当我发现某种类型的漏洞而我不知道如何利用它时阅读相关的文章是非常有用的.假设…
相关网站:http://www.ai4g.com PART I AI AND GAMESCHAPTER1 INTRODUCTIONCHAPTER2 GAME AIPART II TECHNIQUESCHAPTER3 MOVEMENTCHAPTER4 PATHFINDINGCHAPTER5 DECISION MAKINGCHAPTER6 TACTICAL AND STRATEGIC AICHAPTER7 LEARNINGCHAPTER8 BOARD GAMESPART III SUPPORTING…
Series的简单运算 import numpy as np import pandas as pd s1=pd.Series([1,2,3],index=['A','B','C']) print(s1) 结果: A 1 B 2 C 3 dtype: int64 s2=pd.Series([4,5,6,7],index=['B','C','D','E']) print(s2) 结果: B 4 C 5 D 6 E 7 dtype: int64 print(s1+s2)#对应的index相加,NaN…
需求:从steam官网获取英雄数据,即为Json数据,并导入到本地数据库 Json数据是这样的 { "result": { "heroes": [ { "name": "npc_dota_hero_antimage", "id": 1, "localized_name": "Anti-Mage" }, { "name": "npc_dot…