题目链接:https://abc082.contest.atcoder.jp/tasks/abc082_a Time limit : 2sec / Memory limit : 256MB Score : 100 points Problem Statement You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest intege…

题目链接:https://abc082.contest.atcoder.jp/tasks/abc082_b Time limit : 2sec / Memory limit : 256MB Score : 200 points Problem Statement You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearrang…

A - Happy Birthday! Time limit : 2sec / Memory limit : 1000MB Score: 100 points Problem Statement E869120's and square1001's 16-th birthday is coming soon.Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces. E869…

A - ABCxxx Time limit : 2sec / Memory limit : 256MB Score : 100 points Problem Statement This contest, AtCoder Beginner Contest, is abbreviated as ABC. When we refer to a specific round of ABC, a three-digit number is appended after ABC. For example,…

目录 AtCoder Beginner Contest 148 题解 前言 A - Round One 题意 做法 程序 B - Strings with the Same Length 题意 做法 程序 C - Snack 题意 做法 程序 D - Brick Break 题意 做法 程序 E - Double Factorial 题意 做法 程序 F - Playing Tag on Tree 题意 做法 程序 结束语 AtCoder Beginner Contest 148 题解 前言 包…

没看到Beginner,然后就做啊做,发现A,B太简单了...然后想想做完算了..没想到C卡了一下,然后还是做出来了.D的话瞎想了一下,然后感觉也没问题.假装all kill.2333 AtCoder Beginner Contest 052 A题意: 输出大的面积? 思路: max(A*B,C*D); AtCoder Beginner Contest 052 B题意: 枚举过程,然后...太水了.. AtCoder Beginner Contest 052 C题意: 输出N!的因子个数mod1…

A - ABC/ARC Time limit : 2sec / Memory limit : 256MB Score : 100 points Problem Statement Smeke has decided to participate in AtCoder Beginner Contest (ABC) if his current rating is less than 1200, and participate in AtCoder Regular Contest (ARC) oth…

AtCoder Beginner Contest 136 题目链接 A - +-x 直接取\(max\)即可. Code #include <bits/stdc++.h> using namespace std; typedef long long ll; const int N = 2e5 + 5; int main() { ios::sync_with_stdio(false); cin.tie(0); int a, b; cin >> a >> b; cout &…

AtCoder Beginner Contest 137 F 数论鬼题(虽然不算特别数论) 希望你在浏览这篇题解前已经知道了费马小定理 利用用费马小定理构造函数\(g(x)=(x-i)^{P-1}\) \[x=i,g(x)=0\] \[x\ne i ,g(x)=1\] 则我们可以构造 \[f(x)=\sum^{i=0}_{P-1}(-a_i*(x-i)^{P-1}+a_i)\] 对于第\(i\)条式子当且仅当\(a_i=1 \ and \ x=i\)时取到\(1\) 代码写的比较奇怪 const…

A - Rating Goal Time limit : 2sec / Memory limit : 256MB Score : 100 points Problem Statement Takahashi is a user of a site that hosts programming contests.When a user competes in a contest, the rating of the user (not necessarily an integer) changes…