dfs,选择最优路径并输出~ 这道题难度非常炸裂,要求完完整整自己推一遍,DFS才算过关!思路:一遍dfs,过程中要维护两个变量,minCnt 中途停靠最少的站.minTransfer需要换成的最少次数1 可以这样算出一条线路的换乘次数:在line数组里保存每两个相邻站中间的线路是几号线,从头到尾遍历最终保存的路径,preLine为前一小段线路编号,如果当前的节点和前一个节点组成的这条路的编号和preLine不同,说明有一个换乘,就将cnt+1,最后遍历完累加的cnt即是换乘的次数.2 line…

In the big cities, the subway systems always look so complex to the visitors. To give you some sense, the following figure shows the map of Beijing subway. Now you are supposed to help people with your computer skills! Given the starting position of…

In the big cities, the subway systems always look so complex to the visitors. To give you some sense, the following figure shows the map of Beijing subway. Now you are supposed to help people with your computer skills! Given the starting position of…

In the big cities, the subway systems always look so complex to the visitors. To give you some sense, the following figure shows the map of Beijing subway. Now you are supposed to help people with your computer skills! Given the starting position of…

最短路. 记录一下到某个点,最后是哪辆车乘到的最短距离.换乘次数以及从哪个位置推过来的,可以开$map$记录一下. #include<map> #include<set> #include<ctime> #include<cmath> #include<queue> #include<string> #include<stack> #include<vector> #include<cstdio>…

Source: PAT A1131 Subway Map (30 分) Description: In the big cities, the subway systems always look so complex to the visitors. To give you some sense, the following figure shows the map of Beijing subway. Now you are supposed to help people with your…

PAT甲级1131. Subway Map 题意: 在大城市,地铁系统对访客总是看起来很复杂.给你一些感觉,下图显示了北京地铁的地图.现在你应该帮助人们掌握你的电脑技能!鉴于您的用户的起始位置,您的任务是找到他/她目的地的最快方式. 输入规格: 每个输入文件包含一个测试用例.对于每种情况,第一行包含正整数N(<= 100),地铁线数.然后N行跟随,第i(i = 1,...,N)行以格式描述第i条地铁线: M S [1] S [2] ... S [M] 其中M(<= 100)是停止次数,S [i…

可以转到我的CSDN查看同样的文章https://blog.csdn.net/weixin_44385565/article/details/89003683 1131 Subway Map (30 分) In the big cities, the subway systems always look so complex to the visitors. To give you some sense, the following figure shows the map of Beijing…

题目:https://pintia.cn/problem-sets/994805342720868352/problems/994805347523346432 题意: 告诉你一个地铁线路图,站点都是用四位数来编号. 现在问你从某一起点到某一终点,经过站数最少的乘车方式是什么?要输出方案. 如果站数相同要输出换乘较少的. 思路: 首先肯定是搜索没有问题了.因为要输出方案,所以bfs不太方便存答案.很容易想到用dfs 比较麻烦的是输出方案的时候,线路相同的那些站都合并在同一个线路里了.那么我们就再…

In the big cities, the subway systems always look so complex to the visitors. To give you some sense, the following figure shows the map of Beijing subway. Now you are supposed to help people with your computer skills! Given the starting position of…

In the big cities, the subway systems always look so complex to the visitors. To give you some sense, the following figure shows the map of Beijing subway. Now you are supposed to help people with your computer skills! Given the starting position of…

思路:检查某个客人是否有伴侣,如果有,伴侣是否也出现即可. 注意:0个单身狗的时候,不要输出多余的'\n', 否则会出现格式错误. AC代码 #include <stdio.h> #include <string.h> #include <map> #include <string> #include <algorithm> #include <vector> #include <iostream> using names…

思路:DFS遍历 #include <iostream> #include <map> #include <vector> #include <cstdio> using namespace std; const int INF = 0x7fffffff; ; struct Node{ int line, s, e; Node(int xl, int xs, int xe) :line(xl), s(xs), e(xe) {} }; struct Which…

Input our current position and a destination, an online map can recommend several paths. Now your job is to recommend two paths to your user: one is the shortest, and the other is the fastest. It is guaranteed that a path exists for any request. Inpu…

1111 Online Map(30 分) Input our current position and a destination, an online map can recommend several paths. Now your job is to recommend two paths to your user: one is the shortest, and the other is the fastest. It is guaranteed that a path exists…

题意:给出起点和终点,计算求出最短路径(最短路径即所经过的站点最少的),若最短路径不唯一,则选择其中换乘次数最少的一条线路. 思路:本题虽然也是求最短路径,但是此路径是不带权值的,路径长度即所经过的边数,故可以用DFS来求解,而不是用一般的Dijkstra之类的.相信若只是求最短路径,大多数人都会做,就是从起点start开始深度遍历,遍历到终点end时,与全局变量进行比较.更新.本题的关键是,更新最优路径时需要比较“换乘次数”,如何求解它呢?我是这么思考的——首先,考虑用一个二维数组int mp…

Input our current position and a destination, an online map can recommend several paths. Now your job is to recommend two paths to your user: one is the shortest, and the other is the fastest. It is guaranteed that a path exists for any request. Inpu…

专题一  字符串处理 A1001 Format(20) #include<cstdio> int main () { ]; int a,b,sum; scanf ("%d %d",&a,&b); sum=a+b; ) { printf ("-"); sum=-sum; } ; ) { s[top++]=; } ) { s[top++]=sum%; sum/=; } ;i>=;i--) { printf ("%d"…

树(23) 备注 1004 Counting Leaves   1020 Tree Traversals   1043 Is It a Binary Search Tree 判断BST,BST的性质 1053 Path of Equal Weight   1064 Complete Binary Search Tree 完全二叉树的顺序存储,BST的性质 1066 Root of AVL Tree 构建AVL树,模板题,需理解记忆 1079 Total Sales of Supply Chain…

Subway Time Limit: 7000/3500 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 860    Accepted Submission(s): 126Special Judge Problem Description jiefangxuanyan and yiyi cat are universally acknowledged model couple…

Source: PAT (Advanced Level) Practice Reference: [1]胡凡,曾磊.算法笔记[M].机械工业出版社.2016.7 Outline: 基础数据结构: 线性表:栈,队列,链表,顺序表 树:二叉树的建立,二叉树的遍历,完全二叉树,二叉查找树,平衡二叉树,堆,哈夫曼树 图:图的存储和遍历 经典高级算法: 深度优先搜索,广度优点搜索,回溯剪枝 贪心,并查集,哈希映射 最短路径(只考察过单源),拓扑排序(18年9月第一次涉及相关概念,未正式考过),关键路径(未…

Source: PAT A1111 Online Map (30 分) Description: Input our current position and a destination, an online map can recommend several paths. Now your job is to recommend two paths to your user: one is the shortest, and the other is the fastest. It is gu…

1121 Damn Single 模拟 // 1121 Damn Single #include <map> #include <vector> #include <cstdio> #include <iostream> #include <algorithm> using namespace std; map<int, int> m, vis; vector<int> p; ; int a[N]; int main()…

原文链接:http://racksburg.com/choosing-an-http-status-code/ 打开双语对照阅读 有什么能比 HTTP 响应状态码更简单呢?页面渲染了吗?好极了,返回 200.页面不存在?那么是 404.想要跳转到另一个页面?302 或者可能是 301. 我喜欢把 HTTP 状态码想象成无线电波传输的 10 码1.“呼叫,呼叫,我是 White Chocolate Thunder,发现 200 OK.” —— Aaron Patterson (@tenderlov…

Dialogue 1  You took the wrong bus 你做错车了 A:Hi, I want to see the Terra Cotta Warriors in Xi'an. Could you please remind me when we are arriving at that stop?  你好,我想去看西安的秦始皇兵马俑.那一站到的时候你能提醒我一下吗? B:Oh. You took the wrong bus. You need to take Bus 151 wh…

本文转载自:众成翻译 译者:十年踪迹 链接:http://www.zcfy.cc/article/904 原文:http://racksburg.com/choosing-an-http-status-code/ 有什么能比 HTTP 响应状态码更简单呢?页面渲染了吗?好极了,返回 200.页面不存在?那么是 404.想要跳转到另一个页面?302 或者可能是 301. 我喜欢把 HTTP 状态码想象成无线电波传输的 10 码¹.“呼叫,呼叫,我是 White…

本文来源于我在InfoQ中文站翻译的文章.原文地址是:http://www.infoq.com/cn/news/2015/12/how-to-choose-http-status-code 众所周知.每个HTTP响应都会带有一个状态码,只是对于非常多开发人员来说,平时使用最多的几个状态码无外乎就是200.400.404.500等.那其它众多状态码该应用在何种场景中,什么时候应该使用哪些状态码就成为一个值得我们深入思考的问题了. 即便在Facebook这种公司中.那些聪明的开发人员所构建的API也…

应用jQuery菜单插件可以让浏览者在浏览你的网页时获得最好的动态导航.jQuery是一个轻量级.跨浏览器的JavaScript框架(库),效果非常给力,它强调并简化了JavaScript.CSS和HTML之间的交互过程. 使用jQuery,你可以改变网站的外观,使其看起来更加出众,并且容易程度远超你的想象.在这里,你可以提供动态的而且观感非常与众不同的界面,这种界面很受浏览者的欢迎.导航栏作为网页设计的最重要的部件之一,需要非常简洁可用,并且同时也富有创造性,以免使用者因为找不到所要找的按钮而…

北京地铁出行线路规划系统项目总结 GitHub仓库地址:https://github.com/KeadinZhou/SE-Subway Demo地址:http://10.66.2.161:8080/ (校内网) 项目需求 实现一个帮助进行地铁出行路线规划的命令行程序 地铁线路图数据需要与执行程序解耦 支持查询单条线路的所有站点 支持查询任意两站之间通过最少站数的路线 算法设计 项目中最主要的点在于:找出两个站点之间通过最少站数的路线.该点对应的经典模型是"在一个无向图中找出两点之间的最短路径&q…

https://blog.csdn.net/skywalker_only/article/details/38752003 条件函数 下表为Hive支持的一些条件函数. 返回类型 函数名 描述 T if(boolean testCondition, T valueTrue, T valueFalseOrNull) 如果testCondition为真,返回valueTrue,否则返回valueFalseOrNull T COALESCE(T v1, T v2, ...) 返回第一个不是NULL的v…