Problem K K Smallest Sums You're given k arrays, each array has k integers. There are kk ways to pick exactly one element in each array and calculate the sum of the integers. Your task is to find the k smallest sums among them. Input There will be se…

UVA - 11997 id=18702" target="_blank" style="color:blue; text-decoration:none">K Smallest Sums Time Limit: 1000MS   Memory Limit: Unknown   64bit IO Format: %lld & %llu Submit Status You're given k arrays, each array has k…

UVa11997 K Smallest Sums  题目: K Smallest Sums You're given k arrays, each array has k integers. There are kk ways to pick exactly one element in each array and calculate the sum of the integers. Your task is to find the k smallest sums among them. In…

UVA - 11997 K Smallest Sums Time Limit: 1000MS   Memory Limit: Unknown   64bit IO Format: %lld & %llu [Submit]   [Go Back]   [Status] Description   Problem K K Smallest Sums You're given k arrays, each array has k integers. There are kk ways to pick…

11997 - K Smallest Sums You’re given k arrays, each array has k integers. There are kk ways to pick exactly one element in eacharray and calculate the sum of the integers. Your task is to find the k smallest sums among them.InputThere will be several…

题意:K个数组每组K个值,每次从一组中选一个,共K^k种,问前K个小的. 思路:优先队列处理多路归并,每个状态含有K个元素.详见刘汝佳算法指南. #include<iostream> #include<cstdio> #include<cstdlib> #include<stack> #include<queue> #include<vector> #include<map> #include<algorithm&g…

从包含k个整数的k个数组中各选一个求和,在所有的和中选最小的k个值. 思路是多路归并,对于两个长度为k的有序表按一定顺序选两个数字组成和,(B表已经有序)会形成n个有序表 A1+B1<=A1+B2 A2+B1<=A2+B2 ... An+B1<=An+B2 在学习的归并排序的时候是把两个有序的表合并成一个,每次比较只在两个元素之间进行,所以只需要用>比较, 而现在需要同时合并n个有序表,优先队列(堆)就派上用场了.类似归并排序用i和j维护有序表当前考虑元素, 合并的时候,每次取出的…

vjudge 上题目链接:UVA 11997 题意很简单,就是从 k 个数组(每个数组均包含 k 个正整数)中各取出一个整数相加(所以可以得到 kk 个结果),输出前 k 小的和. 这时训练指南上的一道题,这道题的简化版其实在 15 年的广东省省赛出现过,当时是以送分题的形式出现的,可我还是没能做出来,归根到底还是看书不够,接触的题型不够多. ******************************************************大白书上的讲解开始**************…

多路归并 #include<cstdio> #include<cstdlib> #include<algorithm> #include<cstring> #include<queue> #define MAXN 755 using namespace std; int n; int ans[MAXN]; int a[MAXN]; struct Node{ int Val,y; Node(,){ Val=p1,y=p2; } friend boo…

考虑一个简单的问题,两个长度为n的有序数组A和B,从每个数组中各选出一个数相加,共n2中情况,求最小的n个数. 将这n2个数拆成n个有序表: A1+B1≤A1+B2≤... A2+B1≤A2+B2≤... ... An+B1≤An+B2≤... 然后用优先队列合并成一个有序表即可.队列中需要记录两个数的和s,以及在B中的下标b, 比如Aa+Bb出队以后,应该将Aa+B(b+1) = Aa + Bb - Bb + Bb+1 = s - Bb + bb+1入队 对于书上最后的一个思考问题,merge…