HDU-4123-树形dp+rmq+尺取】的更多相关文章

http://acm.hdu.edu.cn/showproblem.php? pid=4123 Problem Description Bob wants to hold a race to encourage people to do sports. He has got trouble in choosing the route. There are N houses and N - 1 roads in his village. Each road connects two houses,…
题意:Bob想要开一个运动会,有n个房子和n-1条路(一棵树),Bob希望每个人都从不同的房子开始跑,要求跑的尽可能远,而且每条路只能走最多一次.Bob希望所有人跑的距离的极差不大于q,如果起点的编号需要连续,那么最多多少个起点. 题解:首先求出每个点所能跑的最大距离(参考hdu2196),问题将转化成给n个数字,求差值不超过q的最大区间.m个询问,n个数,N<=50000 M<=500,所以对于每一次询问可以在O(n)的复杂度求解,st算法求区间最大最小值,尺取法求最大长度. (去年做219…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4123 参考博客:两种解法-树形dp+二分+单调队列(或RMQ)-hdu-4123-Bob’s Race - cc_again的专栏 - CSDN博客  https://blog.csdn.net/cc_again/article/details/12011757 题意:给出一棵有n个点的树,每条树边都有一个权值,对于每一个点,它都有一个编号,我们取它到其他点的最大距离记录下来,现在q个询问,每个询问…
Bob’s Race Time Limit: 5000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3905    Accepted Submission(s): 1245 Problem Description Bob wants to hold a race to encourage people to do sports. He has got trouble…
http://acm.hust.edu.cn/vjudge/problem/25790 这题基本同poj 3162 要注意mx,mx2,vx,vx2每次都要初始化 #include <iostream> #include <string> #include <cstring> #include <cstdlib> #include <cstdio> #include <cmath> #include <algorithm>…
Bob’s Race Time Limit: 5000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Problem Description Bob wants to hold a race to encourage people to do sports. He has got trouble in choosing the route. There are N houses and N - 1 roads…
题目链接 Problem Description Bob wants to hold a race to encourage people to do sports. He has got trouble in choosing the route. There are N houses and N - 1 roads in his village. Each road connects two houses, and all houses are connected together. To…
1.HDU 1520  Anniversary party 2.总结:第一道树形dp,有点纠结 题意:公司聚会,员工与直接上司不能同时来,求最大权值和 #include<iostream> #include<cstring> #include<cmath> #include<queue> #include<algorithm> #include<cstdio> #define max(a,b) a>b?a:b using nam…
The more, The Better Time Limit: 6000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6011    Accepted Submission(s): 3555 Problem Description ACboy很喜欢玩一种战略游戏,在一个地图上,有N座城堡,每座城堡都有一定的宝物,在每次游戏中ACboy允许攻克M个城堡并获得里面的宝物…
/* 题意:n个点组成的树,点和边都有权值,当第一次访问某个点的时候获得利益为点的权值 每次经过一条边,丢失利益为边的权值.问从第i个点出发,获得的利益最大是多少. 输入: 测试样例组数T n n个数每个点的权值 n-1条无向边 a b c a和b是点的标号,c是边的权值. 思路: 注意题目只强调是从某个点出发,并不一定要回到该点. 考虑树形DP. 先随便定义一个树根.然后对于某个点,我们需要维护它子树方向的两个值 1.从该点出发,最终要回到该点的利益的最大值 2.从该点出发,最终不必回到该点的…