poj3253 Fence Repair】的更多相关文章

Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 51411   Accepted: 16879 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…
Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 67319   Accepted: 22142 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…
http://poj.org/problem?id=3253 Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000) planks of wood, each having some integer length Li (1 ≤ Li ≤ 50,000) units. He…
题目描述: Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000) planks of wood, each having some integer length Li (1 ≤ Li ≤ 50,000) units. He then purchases a single…
Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000) planks of wood, each having some integer length Li (1 ≤ Li ≤ 50,000) units. He then purchases a s…
https://vjudge.net/problem/POJ-3253 很经典的题,运用哈夫曼思想,想想很有道理!! 具体实现还是有点绕人,最后被long long卡了一下,看数据大小的时候单纯相乘了.. #include<iostream> #include<cstdio> #include<queue> #include<cstring> #include<algorithm> #include<cmath> #include&l…
分割木板的顺序是自由的,所以每次选择两块最短的板,组合在一起,增加队列,原来两个板出队,直到队列中为空或者仅仅剩下一个板时结束.这里使用优先队列较为方便. #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<queue> #define ll __int64 using namespace std; int len[20005]; i…
我们的小伙伴Bingo真的很调皮,他在上课的路上看到树上有个鸟窝,他就想去把他捅下来,但是鸟窝很高他够不到,于是他就到处找木棍,想把这些木棍接在一起,然后去捅鸟窝.他一共找了N跟木棍 (1 ≤ N ≤ 20,000),每根木棍的长度为 Li (1 ≤ Li ≤ 50,000) .现在他要把这N根木棍连接在一起,每次连接只能把两根木棍连在一起,而且每连接一次都需要花费一些money去买材料,买这些材料要用的money和要连接的两根木棍的长度之和相等(如:把长度分别为5和8的木棍连在一起,买材料就需…
题目链接 http://poj.org/problem?id=3253 题目描述 大意:切长度为a的木条的花费是a,给定最终切好的n段各自的长度,问由原来的一根木条(长度为n段长度和)以最终总花费最小的方法切这n-1下,输出最小花费.(切的中间过程产生的子段不同,所以花费会不同) 例子: 输入: 3 8 5 8 输出: 34 提示: (8+5)+(13+8)=34 题解 过程反着想,就是合并子段的过程. 数据结构:两个单调递增队列. 第一个放进原始的n段的长度. 第二个用来放合并后的段的长度.…
Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 42979   Accepted: 13999 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…
Fence Repair 问题大意:农夫约翰为了修理栅栏,要将一块很长的木块切割成N块,准备切成的木板的长度为L1,L2...LN,未切割前的木板的长度恰好为切割后木板的长度的总和,每次切断木板的时候,需要的开销为这块木板的长度,例如长度为21的木板需要切成长度为5,8,8的三块木板,长为21的木板切成长为13和8的板时,开销为21,.再将长度为13的板切成长度为5和8的板时,开销是13,于是合计开销是34,然后要你求切割完的最小开销是什么. 乍眼看这一道题好像有很多种切割方案,似乎是很难解决的…
Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 23913   Accepted: 7595 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…
Fence Repair Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 32424 Accepted: 10417 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000) pla…
POJ 3253 Fence Repair(修篱笆) Time Limit: 2000MS   Memory Limit: 65536K [Description] [题目描述] Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000) planks of wood, eac…
Fence Repair Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 3253 Appoint description:  hanjiangtao  (2014-11-12) System Crawler  (2015-04-24) Description Farmer John wants to repair a small len…
Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 32916   Accepted: 10638 点我 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,0…
题目 1724: [Usaco2006 Nov]Fence Repair 切割木板 Time Limit: 5 Sec  Memory Limit: 64 MB Description Farmer John想修理牧场栅栏的某些小段.为此,他需要N(1<=N<=20,000)块特定长度的木板,第i块木板的长度为Li(1<=Li<=50,000).然后,FJ去买了一块很长的木板,它的长度正好等于所有需要的木板的长度和.接下来的工作,当然是把它锯成需要的长度.FJ忽略所有切割时的损失—…
倒过来看 , 每次总是选择最短的两块木板合并 , 用heap维护 ------------------------------------------------------------------------------ #include<cstdio> #include<cstring> #include<algorithm> #include<iostream> #include<queue>   #define rep( i , n )…
POJ 3253 Fence Repair (优先队列) Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needsN (1 ≤ N ≤ 20,000) planks of wood, each having some integer lengthLi (1 ≤ Li ≤ 50,000) units. He the…
1724: [Usaco2006 Nov]Fence Repair 切割木板 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 854  Solved: 426[Submit][Status] Description Farmer John想修理牧场栅栏的某些小段.为此,他需要N(1<=N<=20,000)块特定长度的木板,第i块木板的长度为Li(1<=Li<=50,000).然后,FJ去买了一块很长的木板,它的长度正好等于所有需要的木板的…
poj 3253 Fence Repair 优先队列 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000) planks of wood, each having some integer length Li (1 ≤ Li ≤ 50,000) u…
Fence Repair Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000) planks of wood, each having some integer length Li (1 ≤ Li ≤ 50,000) units. He then…
Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 19660   Accepted: 6236 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…
Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 53645   Accepted: 17670 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…
Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 26167   Accepted: 8459 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…
题目链接:http://poj.org/problem?id=3253 Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 61005   Accepted: 20119 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and fi…
Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 28359   Accepted: 9213 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…
Fence Repair Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000) planks of wood, each having some integer length Li (1 ≤ Li ≤ 50,000) units. He then purchases a…
Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 25274   Accepted: 8131 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…
Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 40465   Accepted: 13229 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…