Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: Input: "aba" Output: True Example 2: Input: "abca" Output: True Explanation: You could delete the character 'c'. N…

Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: Input: "aba" Output: True Example 2: Input: "abca" Output: True Explanation: You could delete the character 'c'. N…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 双指针 思路来源 初版方案 进阶方案 日期 题目地址:https://leetcode.com/problems/valid-palindrome-ii/description/ 题目描述 Given a non-empty string s, you may delete at most one character. Judge whether y…

给定一个非空字符串 s,最多删除一个字符.判断是否能成为回文字符串. 示例 1: 输入: "aba" 输出: True 示例 2: 输入: "abca" 输出: True 解释: 你可以删除c字符. 注意: 字符串只包含从 a-z 的小写字母.字符串的最大长度是50000. class Solution { public: bool validPalindrome(string s) { int len = s.size(); if(len == 0) return…

Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: Input: "aba" Output: True Example 2: Input: "abca" Output: True Explanation: You could delete the character 'c'. N…

Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: Input: "aba" Output: True Example 2: Input: "abca" Output: True Explanation: You could delete the character 'c'. 思…

Valid Palindrome Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. For example,"A man, a plan, a canal: Panama" is a palindrome."race a car" is not a palindrome. 验证回文与否,这个估计大家…

[ 问题: ] Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. 直译:给你一个字符串, 判定它是否是回文(仅仅统计字母.数字.其它字符请忽略). For example, "A man, a plan, a canal: Panama" is a palindrome. "race a car"…

翻译 给定一个字符串.确定它是否是回文的,仅仅考虑当中的数字和字符并忽略其它. 比如. "A man, a plan, a canal: Panama" 是回文的. "race a car" 不是回文的 批注: 你是否考虑了字符串可能为空?这样的面试的时候是一个好问题. 对于这问题的意图,我们定义空字符串是回文的. 原文 Given a string, determine if it is a palindrome, considering only alphanu…

题意:给定一个字符串,可以最多去掉一个字符,判断是否可以使该字符串成为一个回文串. 分析:head和tail双指针分别指向字符串首尾,如果s[head] != s[tail],则要么去掉s[head],要么去掉s[tail],只需判断s[head + 1]~s[tail]或s[head]~s[tail-1]是否为回文串即可. class Solution { public: bool judge(string s, int head, int tail){ while(head <= tail)…