HDOJ/HDU 1062 Text Reverse(字符串翻转~)

Problem Description Ignatius likes to write words in reverse way. Given a single line of text which is written by Ignatius, you should reverse all the words and then output them. Input The input contains several test cases. The first line of the inpu…

hdu 1062 Text Reverse 字符串

Text Reverse Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Problem Description Ignatius likes to write words in reverse way. Given…

HDU 1062 Text Reverse（水题，字符串处理）

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1062 解题报告:注意一行的末尾可能是空格,还有记得getchar()吃回车符. #include<cstdio> #include<string.h> #include<iostream> #include<algorithm> #include<cmath> #include<deque> #include<cstdlib>…

题解报告：hdu 1062 Text Reverse

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1062 Problem Description Ignatius likes to write words in reverse way. Given a single line of text which is written by Ignatius, you should reverse all the words and then output them. Input The input con…

【HDOJ】1062 Text Reverse

Ignatius likes to write words in reverse way. Given a single line of text which is written by Ignatius, you should reverse all the words and then output them. Input The input contains several test cases. The first line of the input is a single inte…

HDU 1062 Text Reverse

题意 : 给出你一个句子,让你把句子中每个单词的字母顺序颠倒一下输出. 思路 : 用栈即可,就是注意原来在哪儿有空格就要输出空格. //hdu1062 #include <iostream> #include <stdio.h> #include <string.h> #include <stack> using namespace std ; int main() { int n ; scanf("%d",&n) ; getch…

[hdu 1062] Text Reverse | STL-stack

原题题目大意: t组数据,每组为一行,遇到空格时讲前面的单词反转输出. 题解: 显然的栈题,遇到空格时将当前栈输出清空即可 #include<cstdio> #include<stack> #include<cstring> using namespace std; int t,l; char s[1010]; stack <char> stk; int main() { scanf("%d",&t); getchar(); w…

HDOJ 1062 Text Reverse

Text Reverse Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 12577 Accepted Submission(s): 4743 Problem Description Ignatius likes to write words in reverse way. Given a single line of text w…

1062 Text Reverse

http://acm.hdu.edu.cn/showproblem.php?pid=1062 思路: 最主要的是通过getline函数存取字符串. 如何读取单个单词,并且反向输出? 用\n作为单个单词的判定. 扩展: getline函数的用法,详解 int main() { string line; while(getline(cin,line)) cout<<line<<endl; ; } 大家会发现运行时怎么也跳不出循环,甚至会发生各种莫名其妙的错误.why? getline(…

HDOJ/HDU 1073 Online Judge(字符串处理~)

Problem Description Ignatius is building an Online Judge, now he has worked out all the problems except the Judge System. The system has to read data from correct output file and user's result file, then the system compare the two files. If the two f…

reverse 字符串翻转

头文件 algorithm string s="hello"; reverse(s.begin(),s.end()); char c[]="hello"; reverse(c,c+strlen(c)); 这个函数只要有区间就可以了. 很简单的.…

简单字符串处理 hdu1062 Text Reverse

虽然这个题目一遍AC,但是心里还是忍不住骂了句shit! 花了一个小时,这个题目已经水到一定程度了,但是我却在反转这个操作上含糊不清,并且还是在采用了辅助数组的情况下,关系的理顺都如此之难. 其实我是想到了之前那次保研考试,让给数组里面的数换k位,我也是纠结好久没有写出个所以然,郁闷. #include<stdio.h> #include<string.h> #include<stdlib.h> ]; ]; void divide(char a[],int n) { ,…

Text Reverse

Text Reverse Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13524 Accepted Submission(s): 5161 Problem Description Ignatius likes to write words in reverse way. Given a single line of text w…

（reverse） Text Reverse hdu1062

Text Reverse Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 35208 Accepted Submission(s): 13824 Problem Description Ignatius likes to write words in reverse way. Given a single line of text…

stack的使用-Hdu 1062

Text Reverse Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 51495 Accepted Submission(s): 19692 Problem Description Ignatius likes to write words in reverse way. Given a single line of text…

C字符串翻转

实现字符串翻转,思路很简单,就是首尾字符对调. void reverse(char* str){ char* p = str + strlen(str) - 1;//最后一个字符地址 char temp; while (str<p) { temp = *p;//获取p指向字符串 *p-- = *str;//p 往左边移动,设置值为*str *str++ = temp; } } 注意str<p 这里,代表指针变量的大小,因为同一个字符串的地址,str指向首字母的指针变量的值,p是指向末尾字符的指…

[LeetCode] 190. Reverse Bits 翻转二进制位

Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up:If this function…

【Java笔试】OYO校招Java工程师|牛客平台，算法：字符串翻转。附选择题解析

文章目录 1.Java笔试算法题:字符串翻转 2.单选题: 2.1.同一进程下的多个线程可以共享哪一种资源:data section 2.2.一个树形的叶结点在前序遍历和后序遍历下,可以相同的相对位置出现(√ ) 说理证明: 举例证明: 2.3.下列哪一个命令为删除 sample 数据库的 tb_ame 表(D:drop table sample. tb_ ame) 2.4.在重载运算符函数时,下面(->)运算符必须重载为类成员函数形式 2.5.在对一组记录(54,38,96,23,15,72,…