Average Score Time Limit: 2 Seconds      Memory Limit: 65536 KB Bob is a freshman in Marjar University. He is clever and diligent. However, he is not good at math, especially in Mathematical Analysis. After a mid-term exam, Bob was anxious about his…

水 Average Score Time Limit: 2 Seconds      Memory Limit: 65536 KB Bob is a freshman in Marjar University. He is clever and diligent. However, he is not good at math, especially in Mathematical Analysis. After a mid-term exam, Bob was anxious about hi…

Description 题目描述 Bob is a freshman in Marjar University. He is clever and diligent. However, he is not good at math, especially in Mathematical Analysis. After a mid-term exam, Bob was anxious about his grade. He went to the professor asking about th…

Average Score Time Limit: 2 Seconds      Memory Limit: 65536 KB Bob is a freshman in Marjar University. He is clever and diligent. However, he is not good at math, especially in Mathematical Analysis. After a mid-term exam, Bob was anxious about his…

主题链接:problemId=5373">http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=5373 Bob is a freshman in Marjar University. He is clever and diligent. However, he is not good at math, especially in Mathematical Analysis. After a mid-term exam, Bo…

ZOJ 2819 Average Score Time Limit: 2 Sec  Memory Limit: 60 MB 题目连接 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=5373 Description Bob is a freshman in Marjar University. He is clever and diligent. However, he is not good at math, especia…

题目大意:给出一个由O和X组成的串(长度为1-80),统计得分. 每个O的分数为目前连续出现的O的个数,例如,OOXXOXXOOO的得分为1+2+0+0+1+0+0+1+2+3 解题思路:用一个变量term记录当前O的分数,若出现O,则term+1,若出现X,则term=0: 再用一个sum记录总和,没次加上term即可 /* UVa 1585 Score --- 水题 */ #include <cstdio> #include <cstring> ; int main() { i…

ZYB loves Score Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5268 Description One day,ZYB participated in the BestCoder Contest There are four problems. Their scores are 1000,1500,2000,2500 According to the r…

Information Entropy Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3827 Description Information Theory is one of the most popular courses in Marjar University. In this course, there is an impo…

DFS的核心就是从一种状态出发,转向任意的一个可行状态,直到达到结束条件为止.(个人理解) 下面全是洛谷题,毕竟能找到测试点数据的OJ我就找到这一个....在其他OJ上直接各种玄学问题... P1596 [USACO10OCT] 湖计数Lake Counting DFS入门题,求连通块的. #include<iostream> #include<algorithm> using namespace std; ]={-,-,-, , , ,,};//方向 ]={-, , ,-, ,-…

2679:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1679 2952:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1951 ZOJ:2679先来~ 水题大意:(题目大意:我什么时候改名了哇T T) 给你一个5位数的中间三个字母,还有一个数N让你求能被N整除的最大的五位数. 思路: 直接暴力枚举.... #include<cstdio> int…

2558: 游起来吧!超妹! Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 7  Solved: 3[Submit][Status][Web Board] Description 夏天到了,无聊的超妹跑到了落雪湖里抓鱼吃.结果,游到湖的正中 央时被湖边保安看到了,保安要抓住超妹.我们假设落雪湖是一个半径为r的圆形,超妹在圆形的正中心,速度为1.保安由于不会游泳所以只能沿着湖的边缘奔 跑,速度为n.因为超妹在陆地上的速度是很快的,所以我们假设只要超妹…

Average Score Time Limit: 2 Seconds      Memory Limit: 65536 KB Bob is a freshman in Marjar University. He is clever and diligent. However, he is not good at math, especially in Mathematical Analysis. After a mid-term exam, Bob was anxious about his…

ACM小白...非常费劲儿的学习中,我觉得目前我能做出来的都可以划分在水题的范围中...不断做,不断总结,随时更新 POJ: 1004 Financial Management 求平均值 杭电OJ: 1001  Sum Problem 相加1002  A + B Problem II 模拟人工加法-精度计算 1008 Elevator 很水,但是情况要考虑全面…

题目传送门 /* 水题:找排序找中间的价格,若有两个,选价格大的: 写的是有点搓:) */ #include <cstdio> #include <iostream> #include <algorithm> #include <cmath> #include <cstring> #include <string> #include <map> #include <set> #include <queue…

题目传送门 /* 水题:已知1928年1月1日是星期日,若是闰年加1,总天数对7取余判断就好了: */ #include <cstdio> #include <iostream> #include <algorithm> #include <cmath> #include <cstring> #include <string> #include <map> #include <set> #include <…

题目传送门 /* 水题:) */ #include <cstdio> #include <iostream> #include <algorithm> #include <cmath> #include <cstring> #include <string> #include <map> #include <set> #include <queue> #include <vector>…

LINK:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3778 题意:有n道菜,每道菜需要\(a_i\)道工序,有m个锅可以同时做不同菜,问最小时间. 思路:水题,但要注意最小需要的时间显然是最大的\(a_i\)值,剩下的就是求个均,求个余的事了. /** @Date : 2017-03-24-14.35 * @Author : Lweleth (SoungEarlf@gmail.com) * @Link : http…

题目链接:https://cn.vjudge.net/problem/HDU-1225 水题 代码 #include <algorithm> #include <string> #include <cstdio> #include <map> using namespace std; struct Team{ int score[3]; string name; Team(string name="", int s1=0, int s2=…

CSU 1772 漫漫上学路 Time Limit: 1000MS   Memory Limit: 131072KB   64bit IO Format: %lld & %llu Submit Status Description 对于csuxushu来说,能够在CSU(California State University)上学是他一生的荣幸.CSU校园内的道路设计的十分精巧,由n+1条水平道路和n+1条竖直道路等距交错而成,充分体现了校园深厚的文化底蕴.然而不幸的是CS市每到夏季,天降大雨,…

题目传送门 水题,找出出现次数最多的数字,若多个输出Nobody //#include <bits/stdc++.h> //using namespace std; #include <cstdio> //stdio.h #include <cstring> //string.h #include <algorithm> const int N = 1e3 + 5; struct Hash { int num, cnt; bool operator <…

In computer science, the Knuth-Morris-Pratt string searching algorithm (or KMP algorithm) searches for occurrences of a "word" W within a main "text string" S by employing the observation that when a mismatch occurs, the word itself em…

分析:水题. #include<iostream> using namespace std; #define N 5050 char a[N],b[N],tmp[N]; void Read(char p[]) { getchar(); gets(tmp); while(gets(tmp)) { if(strcmp(tmp,"END")==0) break; if(strlen(tmp)!=0) strcat(p,tmp); strcat(p,"\n");…

L - House Building Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5538 Description Have you ever played the video game Minecraft? This game has been one of the world's most popular game in recent years. The wor…

ScholarshipTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=86686#problem/D Description At last the first term at the University came to its finish. Android Vasya has already passed all the exams and…

GPA Time Limit: 20 Sec  Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=4802 Description In college, a student may take several courses. for each course i, he earns a certain credit (ci), and a mark ranging from A to F, which is c…

那天在机房做的同步赛,比现场赛要慢了一小时开始,直播那边已经可以看到榜了,所以上来就知道A和I是水题,当时机房电脑出了点问题,就慢了好几分钟,12分钟才A掉第一题... A.Average Score 题目大意:给定A序列和B序列,长度分别是n和m,告诉你A序列中的n-1个数和B序列的m个数,求剩下的那个A序列中的数满足:将这个数从A序列移除,然后添加到B序列,使得A序列的平均值变小,B序列的平均值变大.求这个数的取值范围(是整数) 解题思路:求出A序列剩下的n-1个数的平均值,和B序列的平均值…

两题水题: 1.如果一个数能被分解为两个素数的乘积,则称为Semi-Prime,给你一个数,让你判断是不是Semi-Prime数. 2.定义F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2) 让你判断第n项是否能被3整除. 1.ZOJ 2723 Semi-Prime http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1723 打表即可. #include<cstdio>…

Nasty Hacks Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3049    Accepted Submission(s): 2364 Problem Description You are the CEO of Nasty Hacks Inc., a company that creates small pieces of…

LSS Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 128000/64000 KB (Java/Others) SubmitStatistic Next Problem Problem Description Time flies, four years passed, colleage is over. When I am about to leave, a xuemei ask me an ACM  problem, but…