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11. Container With Most Water https://www.cnblogs.com/grandyang/p/4455109.html 用双指针向中间滑动,较小的高度就作为当前情况的高度,然后循环找容量的最大值. 不管两个指针中间有多少高度的柱子,只管两头,因为两头的才决定最大容量. class Solution { public: int maxArea(vector<int>& height) { if(height.empty()) ; ; ,end = h…
Given an m x n matrix of positive integers representing the height of each unit cell in a 2D elevation map, compute the volume of water it is able to trap after raining. Note: Both m and n are less than 110. The height of each unit cell is greater th…
Given an m x n matrix of positive integers representing the height of each unit cell in a 2D elevation map, compute the volume of water it is able to trap after raining. Note:Both m and n are less than 110. The height of each unit cell is greater tha…
Given an m x n matrix of positive integers representing the height of each unit cell in a 2D elevation map, compute the volume of water it is able to trap after raining. Note: Both m and n are less than 110. The height of each unit cell is greater th…
https://leetcode.com/contest/6/problems/trapping-rain-water-ii/ 看到这题,我很高兴,因为我做过!哈哈!其实我现在也写不出来,知道大概思想. 这题是google apactest 2017 round A 的第二题.https://code.google.com/codejam/contest/11274486/dashboard#s=p1 然后,简单一次调试,就ac了.不知道这算不算作弊,做完,我就看见什么instruction,说…
给定一个m x n的矩阵,其中的值均为正整数,代表二维高度图每个单元的高度,请计算图中形状最多能接多少体积的雨水.说明:m 和 n 都是小于110的整数.每一个单位的高度都大于0 且小于 20000.示例:给出如下 3x6 的高度图:[  [1,4,3,1,3,2],  [3,2,1,3,2,4],  [2,3,3,2,3,1]]返回 4. 详见:https://leetcode.com/problems/trapping-rain-water-ii/description/ C++: clas…
Given an m x n matrix of positive integers representing the height of each unit cell in a 2D elevation map, compute the volume of water it is able to trap after raining. Note: Both m and n are less than 110. The height of each unit cell is greater th…
Given an m x n matrix of positive integers representing the height of each unit cell in a 2D elevation map, compute the volume of water it is able to trap after raining. Note: Both m and n are less than 110. The height of each unit cell is greater th…
Given an m x n matrix of positive integers representing the height of each unit cell in a 2D elevation map, compute the volume of water it is able to trap after raining. Note: Both m and n are less than 110. The height of each unit cell is greater th…
题目: Given n * m non-negative integers representing an elevation map 2d where the area of each cell is 1 * 1, compute how much water it is able to trap after raining. 思路: 这道题是前面一道题的一个延伸,http://www.cnblogs.com/AndyJee/p/4821590.html 前面的给出是一维数组,而这里提供的是二…
Given n x m non-negative integers representing an elevation map 2d where the area of each cell is 1 x 1, compute how much water it is able to trap after raining. Example Given 5*4 matrix [12,13,0,12] [13,4,13,12] [13,8,10,12] [12,13,12,12] [13,13,13,…
题意 题目 思路 我一开始想的时候只考虑到一个结点周围的边界的情况,并没有考虑到边界的高度其实影响到所有的结点盛水的高度. 我们可以发现,中间是否能够盛水取决于边界是否足够高于里面的高度,所以这必然是一个从外到内,从小到大的一个过程.因为优先队列必然首先访问的是边界中最小的高度,如果周围小于这个高度那么必然是存在可以盛水的地方,就算是没有也没有任何的损失,只是更新了高度,但是队列依然会从高度小的结点开始访问: 实现 typedef struct node { int x, y; node(int…
题目: Given n x m non-negative integers representing an elevation map 2d where the area of each cell is 1 x 1, compute how much water it is able to trap after raining. Example Given 5*4 matrix [12,13,0,12] [13,4,13,12] [13,8,10,12] [12,13,12,12] [13,13…
Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of…
Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6. The above elevation map is represented by a…
Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of…
Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. Have you met this question in a real interview? Yes Example Given [0,1,0,2,1,0,1,3,2,1,2,1], return…
Container With Most Water 题目链接 Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which togeth…
42. Trapping Rain Water Problem's Link ---------------------------------------------------------------------------- Mean: 在坐标上给你一些竖直放置的条形积木,问你这个积木能够容纳多少液体. analyse: 首先找出最高的积木,然后从前往后一直扫到最高积木,从后往前一直扫到最高积木,两部分体积相加即可. Time complexity: O(N) view code ;  …
LeetCode传送门 https://leetcode.com/problems/trapping-rain-water/ 目标:找出积木能容纳的水的“面积”,如图中黑色部分是积木,蓝色为可容纳水的部分 假设:积木宽度均为1 输入:各个积木的高度 输出:所有积木能容纳水的“面积” 思考过程 1. 逐一求积木的间隔似乎不太容易.特别对于图中3-7积木间的容积,如果可以先求底部(4-6间)的容积,当求解上层(3-7)的容积时,还需要做额外的处理,如减掉底部的高度. 2. 既然如此,可否先求出3-7…
# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 42: Trapping Rain Waterhttps://oj.leetcode.com/problems/trapping-rain-water/ Given n non-negative integers representing an elevation map where the width of each bar is 1,compute how much wa…
leetcode#42 Trapping rain water 这道题十分有意思,可以用很多方法做出来,每种方法的思想都值得让人细细体会. 42. Trapping Rain WaterGiven n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For ex…
leetcode - 42. Trapping Rain Water - Hard descrition Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1],…
Trapping Rain Water Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6. The above elevation map…
https://oj.leetcode.com/problems/trapping-rain-water/ Trapping Rain WaterGiven n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,…
Trapping Rain Water Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example,  Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6. The above elevation ma…
这题放上来是因为自己第一回见到这种题,觉得它好玩儿 =) Trapping Rain Water Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1], retu…
LeetCode 42. Trapping Rain Water Python解法 解题思路: 本思路需找到最高点左右遍历,时间复杂度O(nlogn),以下为向左遍历的过程. 将每一个点的高度和索引存成一个元组 (val, idx) 找到最高的点(可能有多个,任取一个),记为 (now_val, now_idx). 向左找第一个val不大于now_val的点(left_val, left_idx). 以left_val作为水平面,用height[left_val+1, now_val-1]中每一…
一.题目说明 题目是42. Trapping Rain Water,翻译起来就是"接雨水".给n个非负正数代表高度,每个正数宽度为1,让计算能多少雨水.题目难度是Hard 二.我的解法 这个题目是找"坑",然后计算里面可以存的"雨".总共提交了5次,前面几次都是边界错误. 代码如下: #include<iostream> #include<vector> using namespace std; class Solutio…
题目要求:Trapping Rain Water Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6. The above elevatio…