C - ID Time limit : 2sec / Memory limit : 1024MB Score: 300 points Problem Statement In Republic of Atcoder, there are N prefectures, and a total of M cities that belong to those prefectures. City i is established in year Yi and belongs to Prefecture…

Number of Amidakuji 思路:dp dp[i][j]表示经过(i, j) 这个点的方案数 然后一层一层地转移, 对于某一层, 用二进制枚举这一层的连接情况, 判断连接是否符合题意, 然后再进行转移 代码: #pragma GCC optimize(2) #pragma GCC optimize(3) #pragma GCC optimize(4) #include<bits/stdc++.h> using namespace std; #define fi first #def…

B - Palace Time limit : 2sec / Memory limit : 1024MB Score: 200 points Problem Statement A country decides to build a palace. In this country, the average temperature of a point at an elevation of x meters is T−x×0.006 degrees Celsius. There are N pl…

A - Discount Fare Time limit : 2sec / Memory limit : 1024MB Score: 100 points Problem Statement There is a train going from Station A to Station B that costs X yen (the currency of Japan). Also, there is a bus going from Station B to Station C that c…

A - Happy Birthday! Time limit : 2sec / Memory limit : 1000MB Score: 100 points Problem Statement E869120's and square1001's 16-th birthday is coming soon.Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces. E869…

没看到Beginner,然后就做啊做,发现A,B太简单了...然后想想做完算了..没想到C卡了一下,然后还是做出来了.D的话瞎想了一下,然后感觉也没问题.假装all kill.2333 AtCoder Beginner Contest 052 A题意: 输出大的面积? 思路: max(A*B,C*D); AtCoder Beginner Contest 052 B题意: 枚举过程,然后...太水了.. AtCoder Beginner Contest 052 C题意: 输出N!的因子个数mod1…

A - ABC/ARC Time limit : 2sec / Memory limit : 256MB Score : 100 points Problem Statement Smeke has decided to participate in AtCoder Beginner Contest (ABC) if his current rating is less than 1200, and participate in AtCoder Regular Contest (ARC) oth…

AtCoder Beginner Contest 136 题目链接 A - +-x 直接取\(max\)即可. Code #include <bits/stdc++.h> using namespace std; typedef long long ll; const int N = 2e5 + 5; int main() { ios::sync_with_stdio(false); cin.tie(0); int a, b; cin >> a >> b; cout &…

AtCoder Beginner Contest 137 F 数论鬼题(虽然不算特别数论) 希望你在浏览这篇题解前已经知道了费马小定理 利用用费马小定理构造函数\(g(x)=(x-i)^{P-1}\) \[x=i,g(x)=0\] \[x\ne i ,g(x)=1\] 则我们可以构造 \[f(x)=\sum^{i=0}_{P-1}(-a_i*(x-i)^{P-1}+a_i)\] 对于第\(i\)条式子当且仅当\(a_i=1 \ and \ x=i\)时取到\(1\) 代码写的比较奇怪 const…

A - Rating Goal Time limit : 2sec / Memory limit : 256MB Score : 100 points Problem Statement Takahashi is a user of a site that hosts programming contests.When a user competes in a contest, the rating of the user (not necessarily an integer) changes…