hdu 5444 Elven Postman】的更多相关文章

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5444 Elven Postman Description Elves are very peculiar creatures. As we all know, they can live for a very long time and their magical prowess are not something to be taken lightly. Also, they live on tr…
题目链接:pid=5444http://">http://acm.hdu.edu.cn/showproblem.php?pid=5444 Elven Postman Time Limit: 1500/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 1206    Accepted Submission(s): 681 Problem Description E…
Elven Postman Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5444 Description Elves are very peculiar creatures. As we all know, they can live for a very long time and their magical prowess are not something to…
Elven Postman Time Limit: 1500/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 591    Accepted Submission(s): 329 Problem Description Elves are very peculiar creatures. As we all know, they can live for a very…
Time Limit: 1500/1000 MS (Java/Others)   Memory Limit: 131072/131072 K (Java/Others) Problem Description Elves are very peculiar creatures. As we all know, they can live for a very long time and their magical prowess are not something to be taken lig…
Problem Description Elves are very peculiar creatures. As we all know, they can live for a very long time and their magical prowess are not something to be taken lightly. Also, they live on trees. However, there is something about them you may not kn…
Elven Postman Elves are very peculiar creatures. As we all know, they can live for a very long time and their magical prowess are not something to be taken lightly. Also, they live on trees. However, there is something about them you may not know. Al…
HDU 5444 题意:给你一棵树的先序遍历,中序遍历默认是1...n,然后q个查询,问根节点到该点的路径(题意挺难懂,还是我太傻逼) 思路:这他妈又是个大水题,可是我还是太傻逼.1000个点的树,居然用标准二叉树结构来存点,,,卧槽想些什么东西.可以用一维数组,left,right直接指向位置就行了,我这里用的是链表.对于读入的序列,生成一个二叉排序树,同时记录一下路径就可以了,后面居然忘了清空path又wa了一发. #include<iostream> #include<cstdio…
很坑的一道题,读了半天才读懂题,手忙脚乱的写完(套上模板+修改模板),然后RE到死…… 题意: 题面上告诉了我们这是一棵二叉树,然后告诉了我们它的先序遍历,然后,没了……没了! 反复读题,终于在偶然间注意到了这一句——"Not only that, when numbering the rooms, they always number the room number from the east-most position to the west." 它告诉我们,东边的点总是比西边的点…
题意:给出一颗二叉树的先序遍历,默认的中序遍历是1..2.……n.给出q个询问,询问从根节点出发到某个点的路径. 析:本来以为是要建树的,一想,原来不用,其实它给的数是按顺序给的,只要搜结点就行,从根开始搜,如果要到的结点比根结点大,那么一定是向W走, 然后去第一个结点,然后接着判定,一直走,如果找到结束就好.水题.当时想的有点复杂. 代码如下: #include <cstdio> #include <string> #include <cstdlib> #includ…