CodeForces 313C Ilya and Matrix

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CodeForces 313C Ilya and Matrix

Ilya and Matrix Time Limit:1000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64u Submit Status Practice CodeForces 313C Description Ilya is a very good-natured lion. He likes maths. Of all mathematical objects, his favourite one is matri…

codeforces C. Ilya and Matrix 解题报告

题目链接:http://codeforces.com/problemset/problem/313/C 题目意思:给定 4n 个整数(可以组成 2n × 2n 大小的矩阵),问通过对这些整数进行排列,求出 the resulting maximum beauty of the matrix.这个最大值的定义是这样的:先定义m为所有整数中的最大值.如果n = 0,那么,这个beauty 数就是m:否则把2n × 2n 大小的矩阵划分为 2n - 1 × 2n - 1- 大小的子矩阵,那么 bea…

codeforces Ilya and Matrix

http://codeforces.com/contest/313/problem/C #include <cstdio> #include <cstring> #include <algorithm> using namespace std; ]; int main() { int n; scanf("%d",&n); ; i<n; i++) { scanf("%lld",&a[i]); } sort(a,…

Educational Codeforces Round 40 C. Matrix Walk( 思维)

Educational Codeforces Round 40 (Rated for Div. 2) C. Matrix Walk time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output There is a matrix A of size x × y filled with integers. For every , *A**i, …

codeforces 486B.OR in Matrix 解题报告

题目链接:http://codeforces.com/problemset/problem/486/B 题目意思:给出一个m行n列的矩阵B(每个元素只由0/1组成),问是否可以利用矩阵B,通过一定的运算逆回来求出矩阵A(行和列数都跟B相同).可以的话输出"YES" 并输出矩阵A,否则输出 "NO".运算如下: 也就是,Bij 是通过 A 矩阵第 i 行中所有的数做或(|) 运算接着再跟所有第 j 列中所有的数做或运算求出来的.or 运算就是除了所有元素都为 0…

Codeforces 518D Ilya and Escalator

http://codeforces.com/problemset/problem/518/D 题意:n个人,每秒有p的概率进电梯,求t秒后电梯里人数的期望考虑dp:f[i][j]代表第i秒有j个人的概率,f[0][0]=1,f[i][j]=f[i-1][j-1]*p+f[i-1][j]*(1-p),特别有:f[i][n]=f[i-1][n]+f[i-1][n-1]*p #include<cstdio> #include<cmath> #include<algorithm&g…

codeforces 842C Ilya And The Tree

Ilya is very fond of graphs, especially trees. During his last trip to the forest Ilya found a very interesting tree rooted at vertex 1. There is an integer number written on each vertex of the tree; the number written on vertex i is equal to ai. Ily…