ZOJ 2680 Clock()数学】的更多相关文章

主题链接:problemId=1680" target="_blank">http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1680 There is an analog clock with two hands: an hour hand and a minute hand. The two hands form an angle. The angle is measured as the small…
Clock Time Limit: 2 Seconds      Memory Limit: 65536 KB You are given a standard 12-hour clock with analog display, an hour hand and a minute hand. How many times does the minute hand pass the hour hand in a given time interval? Sample Input 12 50 1…
Ones Time Limit: 2 Seconds      Memory Limit: 65536 KB Given any integer 0 <= n <= 10000 not divisible by 2 or 5, some multiple of n is a number which in decimal notation is a sequence of 1's. How many digits are in the smallest such a multiple of n…
http://acm.zju.edu.cn/onlinejudge/showContestProblem.do?problemId=5564   根据它的定义是行最小,列最大. 可以证明鞍点是唯一的. 单独考虑每一个元素的贡献,它能成为鞍点的情况有: 1.在这一行中,<= a[i][j]的元素肯定要删除,那么剩下k1个大于他a[i][j]的,当然a[i][j]本身不能删除 2.在这一列中,>= a[i][j]的元素肯定要删除,那么剩下k2个小于a[i][j]的,当然a[i][j]本身不能删除…
杨宗纬的歌"这一路走来" 还蛮好听的,这首歌静静的躺在我的音乐盒某个阴暗的角落里,今天随机播放才发现的,哈哈. 数学一直是硬伤...... ------------------------------------------------数学硬伤的分割线------------------------------------------------ ZOJ:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=910 POJ…
题目传送门 /* 杭电一题(ACM_steps 2.2.4)的升级版,使用到高精度: 这次不是简单的猜出来的了,求的是GCD (n, k) == 1 最大的k(1, n/2): 1. 若n是奇数,则k = (n-1) / 2: 2. 若n是偶数,讨论(n-1)/2 的奇偶性,若不是奇数,则是n/2-2: 详细解释(证明):http://www.xuebuyuan.com/1552889.html */ #include <cstdio> #include <iostream> #i…
题目链接: POJ:id=3100" style="font-size:18px">http://poj.org/problem? id=3100 ZOJ:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1818 HDU:pid=2740">http://acm.hdu.edu.cn/showproblem.php?pid=2740 Description Given positive…
ZOJ Problem Set - 3593 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3593 One Person Game Time Limit: 2 Seconds      Memory Limit: 65536 KB There is an interesting and simple one person game. Suppose there is a number axis under your f…
题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3230 Programming is fun, Aaron is addicted to it. In order to improve his programming skill, he decides to solve one programming problem per day. As you know, different problems have d…
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=494 题目大意: 一只蜗牛要从爬上n英寸高的地方,他速度为u每分钟,他爬完u需要休息1分钟,且他休息时下滑d英寸,问他什么时候爬出去. 吐槽: 小学的数学题编程了编程题,简直丧心病狂. 思路: 数据量小直接模拟即可. 也可以用数学推导 模拟板: #include<cstdio> int main() { int n,u,d; while(~scanf("%d%d%d…