给出一个区间的集合, 请合并所有重叠的区间.示例:给出 [1,3],[2,6],[8,10],[15,18],返回 [1,6],[8,10],[15,18].详见:https://leetcode.com/problems/merge-intervals/description/ Java实现: /** * Definition for an interval. * public class Interval { * int start; * int end; * Interval() { st…
Given a collection of intervals, merge all overlapping intervals. For example, Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. 这道和之前那道Insert Interval 插入区间 很类似,这次题目要求我们合并区间,之前那题明确了输入区间集是有序的,而这题没有,所有我们首先要做的就是给区间集排序,由于我们要排序的是个结构体,所以我们要定义自…
Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 思路: 我们首先要做的就是给区间集排序,由于我们要排序的是个结构体,所以我们要定义自己的comparator,才能用sort来排序,我们以start的值从小到大来排序,排完序我们就可以开始合并了,首先把第一个区间存入结果…
题目: Given a collection of intervals, merge all overlapping intervals. Example 1: Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]] Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into [1,6]. Example 2: Input: [[1,4]…
Given a collection of intervals, merge all overlapping intervals. Example 1: Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]] Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into [1,6]. Example 2: Input: [[1,4],[4,…
Given a collection of intervals, merge all overlapping intervals. Example 1: Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]] Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into [1,6]. 题意: 给定一些区间,将重叠部分合并. 思路: 将原in…
Given a collection of intervals, merge all overlapping intervals. For example, Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. 解题思路一: 用两个指针startIndex和endIndex来维护每次添加intervals的start和end的位置,然后分类讨论即可,JAVA实现如下: public List<Interval> merge…
Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 题目没有说所有间隔的start是依次增加的.所以,为了方便讨论,我们要将所有间隔按照start升序排列.因为间隔增加,就只需讨论end和下一个间隔. 结果集中是没有交叉出现的,排序后,遍历下一个时,只会跟结果集最后一个产…
Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 题目标签:Array 这道题目给了我们一个区间的list,让我们返回一个list,是合并了所有有重叠的区间之后的list.这道题目的关键在于如何判断两个区间有重叠,根据原题给的例子可以看出,在按照每个区间的start排序…
[056-Merge Intervals(区间合并)] [LeetCode-面试算法经典-Java实现][全部题目文件夹索引] 原题 Given a collection of intervals, merge all overlapping intervals. For example, Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. 题目大意 给定一个区间集合,合并有重叠的区间. 解题思路 先对区间进行排序.按開始…
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […
Merge Intervals Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 解题思路: 根据start对区间进行排序,然后依次遍历进行区间合并. /** * Definition for an interval. * struct Interval { * int…
Interval的合并时比较常见的一类题目,网上的Amazon面经上也有面试这道题的记录.这里以LeetCode上的例题做练习. Merge Intervals Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. /** * Definition for an inter…
题目:合并区间 难度:Medium 题目内容: Given a collection of intervals, merge all overlapping intervals. 翻译: 给定一个区间的集合,合并所有重叠的区间. Example 1: Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]] Example 2: Input: [[1,4],[4,5]] Output: [[1,5]] 我的思路:因为…
