A and B and Compilation Errors time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A and B are preparing themselves for programming contests. B loves to debug his code. But before he runs the…

B. A and B and Compilation Errors time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A and B are preparing themselves for programming contests. B loves to debug his code. But before he runs t…

SQL> create or replace function 2 remove_constants(p_query in varchar2) return varchar2 3 as 4 l_query long; 5 l_char varchar2(1); 6 l_in_quotes boolean default FLASE; 7 begin 8 for i in 1..length(p_query) 9 loop 10 l_char :=substr(p_query,i,1); 11 i…

B. A and B and Compilation Errors time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A and B are preparing themselves for programming contests. B loves to debug his code. But before he runs t…

A and B are preparing themselves for programming contests. B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code. Initially, the compiler displayed n compilation errors, each of them is repr…

B. Maximum Submatrix 2 time limit per test 2 seconds memory limit per test 512 megabytes input standard input output standard output You are given a matrix consisting of digits zero and one, its size is n × m. You are allowed to rearrange its rows. W…

题目意思还是蛮简单的,看 输入数据输出数据还是比较明显的 我用排序来写还是可以AC的 //#pragma comment(linker, "/STACK:16777216") //for c++ Compiler #include <stdio.h> #include <iostream> #include <fstream> #include <cstring> #include <cmath> #include <s…

解决方案: sqlplus / as sysdba grant execute on UTL_I18N to scott; grant execute on DBMS_CRYPTO to scott;…

出现这错误的话,存储过程还是会成功创建的,创建好后再逐个打开查找存储过程的问题 问题:基本上就是存储过程里面的表不存在,dblink 不存在    ,用户名.xx表  要么用户名不存在要么表不存在 创建好后,右键view存储过程,下面消息栏就会提示表不存在什么什么之类的,修改完F8按下执行即可…

[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 开3个map, 存在map里面: 然后迭代第一个和第二个map; 分别与第二个和第三个map比较就可以了 [代码] #include <bits/stdc++.h> using namespace std; const int N = 1e5; map<int,int> m[3]; int n; int main() { cin >> n; for (int i = 0;i<3;i++){ for…