Level: Hard 题目描述: Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and put. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, othe…
请珍惜小编劳动成果,该文章为小编原创,转载请注明出处. LRU算法,即Last Recently Used ---选择最后一次訪问时间距离当前时间最长的一页并淘汰之--即淘汰最长时间没有使用的页 依照最多5块的内存分配情况,实现LRU算法代码例如以下: public class LRU { private int theArray[]; private int back; //定义队尾 private int currentSize; //队列中存放元素个数 private int maxSiz…
请珍惜小编劳动成果,该文章为小编原创,转载请注明出处. LRU算法,即Last Recently Used ---选择最后一次访问时间距离当前时间最长的一页并淘汰之--即淘汰最长时间没有使用的页 按照最多5块的内存分配情况,实现LRU算法代码如下: public class LRU { private int theArray[]; private int back; //定义队尾 private int currentSize; //队列中存放元素个数 private int maxSize=…
题目 Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.…
一道LeetCode OJ上的题目,要求设计一个LRU(Least Recently Used)算法,题目描述如下: Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the k…