P1825 [USACO11OPEN]玉米田迷宫Corn Maze 题目描述 This past fall, Farmer John took the cows to visit a corn maze. But this wasn't just any corn maze: it featured several gravity-powered teleporter slides, which cause cows to teleport instantly from one point in…

P1825 [USACO11OPEN]玉米田迷宫Corn Maze 题目描述 This past fall, Farmer John took the cows to visit a corn maze. But this wasn't just any corn maze: it featured several gravity-powered teleporter slides, which cause cows to teleport instantly from one point in…

题目描述 This past fall, Farmer John took the cows to visit a corn maze. But this wasn't just any corn maze: it featured several gravity-powered teleporter slides, which cause cows to teleport instantly from one point in the maze to another. The slides w…

https://www.luogu.org/problem/show?pid=1825 题目描述 This past fall, Farmer John took the cows to visit a corn maze. But this wasn't just any corn maze: it featured several gravity-powered teleporter slides, which cause cows to teleport instantly from on…

题目链接:https://www.luogu.org/problemnew/show/P1825 带有传送门的迷宫问题 #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; const int maxn = 2001; char map[maxn][maxn]; int fx[4] = {0, 1, 0, -1};…

题目描述 This past fall, Farmer John took the cows to visit a corn maze. But this wasn't just any corn maze: it featured several gravity-powered teleporter slides, which cause cows to teleport instantly from one point in the maze to another. The slides w…

P1825 传送门 简单的题意 就是一个有传送门的迷宫问题(我一开始以为是只有1个传送门,然后我就凉了). 大体思路 先把传送门先存起来,然后跑一下\(BFS\). 然后,就做完了. 代码鸭 #include <iostream> #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> #include <iomanip> #include…

3299: [USACO2011 Open]Corn Maze玉米迷宫 Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 137  Solved: 59[Submit][Status][Discuss] Description 今年秋天,约翰带着奶牛们去玩玉米迷宫.迷宫可分成NxM个格子,有些格子种了玉 米,种宥玉米的格子无法通行. 迷宫的四条边界上都是种了玉米的格子,其屮只有一个格子 没种,那就是出口. 在这个迷宫里,有一些神奇的传送点6每个传送点…

P1879 [USACO06NOV]玉米田Corn Fields 状压dp水题 看到$n,m<=12$,肯定是状压鸭 先筛去所有不合法状态,蓝后用可行的状态跑一次dp就ok了 #include<iostream> #include<cstdio> #include<cstring> #define re register using namespace std; const int p=1e9; ],f[][]; ][],len[]; int mod(int a)…

玉米田Corn Fields 题目链接 此题和互不侵犯状压DP的做法类似 f[i][j]表示前i行,第i行种植(1)/不种植(0)构成的二进制数为j时的方案数 首先我们可以预处理出所有一行中没有两个相邻的1的二进制数 然后进行暴力的DP #include<cstdio> #define mod 100000000 #define N 13 #define M 4100 int n,m,f[N][M],a[N]; ],cnt,ans; inline int read(){ char c=getc…