LeetCode之Min Stack 实现最小栈】的更多相关文章

LeetCode相关的网上资源比较多,看到题目一定要自己做一遍,然后去学习参考其他的解法. 链接: https://oj.leetcode.com/problems/min-stack/ 题目描述: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Remov…
翻译 设计支持push.pop.top和在常量时间内检索最小元素的栈. push(x) -- 推送元素X进栈 pop() -- 移除栈顶元素 top() -- 得到栈顶元素 getMin() -- 检索栈的最小元素 原文 Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop…
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…
946. Validate Stack Sequences 题目描述 Given two sequences pushed and popped with distinct values, return true if and only if this could have been the result of a sequence of push and pop operations on an initially empty stack. 示例 示例1 Input: pushed = [1,…
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…
题目 Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimu…
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…
题目描述: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the min…
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…
155. Min Stack class MinStack { public: /** initialize your data structure here. */ MinStack() { } void push(int x) { if(s1.empty() && s2.empty()){ s1.push(x); s2.push(x); } else{ if(x < s2.top()){ s1.push(x); s2.push(x); } else{ s1.push(x); s2…
tag: 栈(stack) 题目描述 设计一个支持 push,pop,top 操作,并能在常数时间内检索到最小元素的栈. push(x) -- 将元素 x 推入栈中. pop() -- 删除栈顶的元素. top() -- 获取栈顶元素. getMin() -- 检索栈中的最小元素. 示例: MinStack minStack = new MinStack(); minStack.push(-2); minStack.push(0); minStack.push(-3); minStack.get…
https://leetcode.com/problems/min-stack/ #include <vector> #include <queue> #include <map> #include <iostream> using namespace std; class MinStack { public: vector<int> vec; priority_queue<int,vector<int>,greater<…
[题目] Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the mini…
1.原文问题描述: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the…
题目描述: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.push(x) -- Push element x onto stack.pop() -- Removes the element on top of the stack.top() -- Get the top element.getMin() -- Retrieve the minimum…
题目: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minim…
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…
题意:设计一个能输出栈内最小值的栈 该题设计两个栈,一个栈是正常的栈s,而另一个是存最小值的栈sm 在push时要判断sm是否为空,如果为空或者非空但是栈顶元素大于等于插入值的 需要在sm中插入x 同样地在pop时,s的元素被删除了,那么sm中的也应该被删除. 通过这些操作维护sm能很巧妙在O(1)复杂度得到最小值. class MinStack { public: stack<int> sm; stack<int> s; void push(int x) { s.push(x);…
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack.    pop() -- Removes the element on top of the stack.    top() -- Get the top element.    getMin() -- Retrieve the…
今天做了一道MinStack的题,深深的感到自己C++还完全没有学好!!! #include <iostream> #include <stack> using std::stack; class MinStack { public: stack<int> st; stack<int> stm; void push(int x) { st.push(x); if(stm.empty() || stm.top()>=x) { stm.push(x); }…
LeetCode 155:最小栈 Min Stack 设计一个支持 push,pop,top 操作,并能在常数时间内检索到最小元素的栈. push(x) -- 将元素 x 推入栈中. pop() -- 删除栈顶的元素. top() -- 获取栈顶元素. getMin() -- 检索栈中的最小元素. Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. pu…
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…
3.2 How would you design a stack which, in addition to push and pop, also has a function min which returns the minimum element? Push, pop and min should all operate in O(1) time. LeetCode上的原题,请参见我之前的博客Min Stack 最小栈.…
题目 带最小值操作的栈 实现一个带有取最小值min方法的栈,min方法将返回当前栈中的最小值. 你实现的栈将支持push,pop 和 min 操作,所有操作要求都在O(1)时间内完成. 解题 可以定义一个数组或者其他的存储最小值,第i个元素,表示栈中前i个元素的最小值. 定义两个ArrayList来存储栈,一个ArrayList存储当前栈中的元素,一个ArrayList存储最小栈,并且其第i个元素表示栈中前i个元素的最小值,这样两个栈的长度是始终一样的 入栈:最小栈需要加入的元素是 当前要入的元…
Implement a stack with min() function, which will return the smallest number in the stack. It should support push, pop and min operation all in O(1) cost. Notice min operation will never be called if there is no number in the stack. Have you met this…
1- 问题描述 Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the m…
这是悦乐书的第177次更新,第179篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第36题(顺位题号是155).设计一个支持push,pop,top和在恒定时间内检索最小元素的堆栈. push(x) - 将元素x推入堆栈. pop() - 删除堆栈顶部的元素. top() - 获取顶部元素. getMin() - 检索堆栈中的最小元素. 例如: MinStack minStack = new MinStack(); minStack.push(-2); minSta…
下面题目是LeetCode算法155题: https://leetcode.com/problems/min-stack/ 题目1:最小函数min()栈 设计一个支持 push,pop,top 操作,并能在常数时间内检索到最小元素的栈. push(x) -- 将元素 x 推入栈中. pop() -- 删除栈顶的元素. top() -- 获取栈顶元素. getMin() -- 检索栈中的最小元素. package com.good.good.study.stack; import java.uti…
LeetCode初级算法--设计问题02:最小栈 搜索微信公众号:'AI-ming3526'或者'计算机视觉这件小事' 获取更多算法.机器学习干货 csdn:https://blog.csdn.net/baidu_31657889/ csdn:https://blog.csdn.net/abcgkj/ github:https://github.com/aimi-cn/AILearners 一.引子 这是由LeetCode官方推出的的经典面试题目清单~ 这个模块对应的是探索的初级算法~旨在帮助入…
原标题:https://oj.leetcode.com/problems/min-stack/ Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the…