Time Limit: 8000/4000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description NPY's girlfriend blew him out!His honey doesn't love him any more!However, he has so many girlfriend candidates.Because there are too many girls and…

NPY and girls Problem Description NPY's girlfriend blew him out!His honey doesn't love him any more!However, he has so many girlfriend candidates.Because there are too many girls and for the convenience of management, NPY numbered the girls from 1 to…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5142 NPY and FFT Description A boy named NPY is learning FFT algorithm now.In that algorithm,he needs to do an operation called "reverse".For example,if the given number is 10.Its binary representai…

NPY and girls 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5145 莫队算法 注意到没有修改区间的操作,使用莫队算法:将整个区间分成若干个块,将询问区间按块优先升序排序,同块内按区间右界升序排序,添加一个元素,满足条件的值sum就变为sum=(sum*times[a[r]]/(r-l+1));减少一个值同理.从第一个区间一直推到最后一个区间即可.(之前TLE一直以为是区间大小的问题,现在发现是这句话while(x<0)x+=M,不过…

人生中第一道莫队,本来以为是一道水题的.. 首先这题只有区间查询,没有修改操作,使用莫队比较明显,但统计答案有点麻烦.. 根据题意,在n个人里选m个不相同种类的人,设第i种人数量为ai,总方案为c(n,a1)*c(n-a1,a2)*c(n-a1-a2,a3)*...*c(n-a1-a2-...-an-1,an).而我们要用O(1)的复杂度实现转移,那么我们可以用c(n,m)=c(n-1,m-1)*n/m来实现转移,在模意义下除法必须使用逆元,那么我们利用费马小定理预处理出每个值的逆元就好了..…

NPY and shot Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1035    Accepted Submission(s): 428   Problem Description NPY is going to have a PE test.One of the test subjects is throwing the sh…

在阅读有关代码的时候,发现一段代码写为: data_frames = np.load(os.path.join(video_root_path, '{}/{}_frames_{:02d}.npy'.format(dataset, train_or_test, i+1))) 对于这段代码的解答如下: 首先是下载一段代码,这段代码应的路径使用join函数拼接起来,即所需要下载的文件路径为: video_root_path/dataset/train_or_test_i+1.py,对于其中 '{}/{…

import numpy as npc = np.load( "vgg16.npy" )   #npy的文件名x = c.item()     #此时,x的type是一个字典name = 'conv1_1'print x['fc7'][0].shape…

1. sys.argv[1:]  # 在控制台进行参数的输入时,只使用第二个参数以后的数据 参数说明:控制台的输入:python test.py what, 使用sys.argv[1:],那么将获得what这个数值 # test.py import sys print(sys.argv[1:]) 2. tf.split(value=x, num_or_size_split=2, axis=3) # 对数据进行切分操作,比如原始维度为[1, 227, 227, 96], 切分后的维度为[2, 1,…

npy文件--Numpy专用的二进制格式np.load()和np.save()是读写磁盘数组数据的两个重要函数.使用时,数组会以未压缩的原始二进制格式保存在扩展名为.npy的文件中. import numpy as np # 将数组以二进制格式保存到磁盘 arr=np.arange(5) np.save('test',arr) # 读取数组 print(np.load('test.npy')) 保存为.npy文件后如果使用记事本等工具打开浏览会出现乱码,所以如果想在保存后能够浏览内容的话建议不要…