LeetCode - Merge Interval.】的更多相关文章

Interval的合并时比较常见的一类题目,网上的Amazon面经上也有面试这道题的记录.这里以LeetCode上的例题做练习. Merge Intervals Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. /** * Definition for an inter…
Merge Intervals 2014.2.26 21:28 Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. Solution: The problem didn't guarantee that the set of intervals is sorted, so…
题目 Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). Yo…
lc57 Insert Interval 仔细分析题目,发现我们只需要处理那些与插入interval重叠的interval即可,换句话说,那些end早于插入start以及start晚于插入end的interval都可以保留.我们只需要两个指针,i&j分别保存重叠interval中最早start和最晚end即可,然后将interval [i, j]插入即可 class Solution { public int[][] insert(int[][] intervals, int[] newInte…
56. Merge Interval 0. 参考文献 序号 文献 1 花花酱 LeetCode 56. Merge Intervals 2 [LeetCode] Merge Intervals 合并区间 1. 题目 Given a collection of intervals, merge all overlapping intervals. Example 1: Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]…
作者:jostree  转载请注明出处 http://www.cnblogs.com/jostree/p/4051169.html 题目链接:leetcode Insert Interval 使用模拟的方法,把需要插入的区间和每一个给定的区间进行比较,有三种情况: 1.给定区间的起点小于要插入区间的终点,并且区间还未被查入过,那么插入区间. 2.给定区间的终点大于要插入区间的起点,或者插入区间已经被插入过了,那么插入给定区间. 3.不满足以上两种情况,说明给定区间与插入区间有交集,那么把需要插入…
LintCode 156: Merge Interval 题目描述 给出若干闭合区间,合并所有重叠的部分. 样例 给出的区间列表 => 合并后的区间列表: [ [ [1, 3], [1, 6], [2, 6], => [8, 10], [8, 10], [15, 18] [15, 18] ] ] Fri Feb 24 2017 思路 首先将区间们按照开始元素的大小排序,然后从头到尾遍历一遍,若遇到该区间的开始元素小于前一个区间的结束元素时,将两个区间合并. 区间合并可以直接修改前一个区间的结束…
Merge Interval: Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 算法分析:首先要对给定序列排序.然后再去遍历合并. class Interval { int start; int end; Interval() { start = 0; end = 0…
题目: Given a collection of intervals, merge all overlapping intervals. For example, Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. 题解: 这道题主要难点是改写Comparator. Comparator接口定义了两个方法:compare( )和equals( ).这里给出的compare( )方法按顺序比较了两个元素: int comp…
Given two sorted integer arrays A and B, merge B into A as one sorted array. Note:You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are m …
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9], insert and merge…
Given a collection of intervals, merge all overlapping intervals. For example, Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. 这道和之前那道Insert Interval 插入区间 很类似,这次题目要求我们合并区间,之前那题明确了输入区间集是有序的,而这题没有,所有我们首先要做的就是给区间集排序,由于我们要排序的是个结构体,所以我们要定义自…
原题地址:https://oj.leetcode.com/problems/insert-interval/ 题意: Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times…
原题地址:https://oj.leetcode.com/problems/merge-intervals/ 题意: Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 解题思路:先将区间按照每个start的值来排序,排好序以后判断一个区间的start值是否处在前一个区间…
Merge IntervalsGiven a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. SOLUTION 1: 1. 先使用Comparator 的匿名类对intervels进行排序. 2. 把Intervals遍历一次,依次一个一个merge到第1个interval. 把第1…
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 这道题让我们合并k个有序链表,之前我们做过一道Merge Two Sorted Lists 混合插入有序链表,是混合插入两个有序链表.这道题增加了难度,变成合并k个有序链表了,但是不管合并几个,基本还是要两两合并.那么我们首先考虑的方法是能不能利用之前那道题的解法来解答此题.答案是肯定的,但是需要修改…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 这道混合插入有序链表和我之前那篇混合插入有序数组非常的相似Merge Sorted Array,仅仅是数据结构由数组换成了链表而已,代码写起来反而更简洁.具体思想就是新建一个链表,然后比较两个链表中的元素值,把较小的…
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […
Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 题目的意思是将相交得区间合并,典型的贪心算法 首先将区间先按照start进行排序, 然后保存先前区间的start和end 如果当前的start > 先前的end,说明当前的区间与之前的区间不想交,则将先前的区间放入结果中…
感觉有一点进步了,但是思路还是不够犀利. /** * Definition for an interval. * struct Interval { * int start; * int end; * Interval() : start(0), end(0) {} * Interval(int s, int e) : start(s), end(e) {} * }; */ class Solution { public: vector<Interval> merge(vector<In…
Question: Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. --------------------------------------- Solution: public class Solution { class IntervalAsc implemen…
我在Github上新建了一个解答Leetcode问题的Project, 大家可以参考, 目前是Java 为主,里面有leetcode上的题目,解答,还有一些基本的单元测试,方便大家起步. 题目: Given two sorted integer arrays A and B, merge B into A as one sorted array. Note:You may assume that A has enough space (size that is greater or equal…
https://oj.leetcode.com/problems/merge-k-sorted-lists/ 归并K已经整理阵列,和分析算法的复杂. 解决报告:无论是不考虑优化,最简单的实现是要重新走路List<ListNode>.对当中每一个链表同当前链表做一遍类似于归并排序最后一步的merge操作. 算法复杂度是O(KN) public class Solution { ListNode mergeTwoLists(ListNode list1, ListNode list2) { Lis…
Given two binary trees and imagine that when you put one of them to cover the other, some nodes of the two trees are overlapped while the others are not. You need to merge them into a new binary tree. The merge rule is that if two nodes overlap, then…
原题地址:https://oj.leetcode.com/problems/merge-sorted-array/ 题意:Given two sorted integer arrays A and B, merge B into A as one sorted array. 解题思路:归并排序的归并这一步的实现,原理很多地方都有.使用一个tmp临时数组进行归并. 代码: class Solution: # @param A a list of integers # @param m an int…
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Input: intervals = [[1,3],[6,9]], newInterval…
Given an array nums of n integers and an integer target, are there elements a, b, c, and d in nums such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target. Note: The solution set must not contain dupli…
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […
Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. Show Tags Array Sort   这题其实想好思路很好解决,对于框,如果下个框开始在 其中间,则连在一起,否则单独为一个,这需要按start 排序便可以了,因为类中写自定义比较函数比较麻烦,所以一次写了好几个…
https://oj.leetcode.com/problems/insert-interval/ 给出有序的区间来,再插入进去一个,也就是区间合并. 刚开始确立了几个思路,看要插入的区间的start和end分别位于什么位置.区分是在空闲处还是在一个区间里面,并且还要判断跨越了几个区间,并且要进行数组元素的后移之类的.写了代码比较麻烦,于是想新的思路.如下:新建立一个数组,这样从前往后扫描老数组和要插入元素的关系,如果还没到插入元素,则正常将老数组元素复制到新数组里面,如果到了要插入的元素,则开…