[POJ3277]City Horizon 试题描述 Farmer John has taken his cows on a trip to the city! As the sun sets, the cows gaze at the city horizon and observe the beautiful silhouettes formed by the rectangular buildings. The entire horizon is represented by a numb…

POJ 3277 City Horizon Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 18466 Accepted: 5077 Description Farmer John has taken his cows on a trip to the city! As the sun sets, the cows gaze at the city horizon and observe the beautiful silho…

http://poj.org/problem?id=3277 City Horizon Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 15255   Accepted: 4111 Description Farmer John has taken his cows on a trip to the city! As the sun sets, the cows gaze at the city horizon and o…

1645: [Usaco2007 Open]City Horizon 城市地平线 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 315  Solved: 157[Submit][Status] Description Farmer John has taken his cows on a trip to the city! As the sun sets, the cows gaze at the city horizon and observe t…

Description Farmer John has taken his cows on a trip to the city! As the sun sets, the cows gaze at the city horizon and observe the beautiful silhouettes formed by the rectangular buildings. The entire horizon is represented by a number line with N…

BZOJ_1654_[Usaco2007 Open]City Horizon 城市地平线_扫描线 Description N个矩形块,交求面积并. Input * Line 1: A single integer: N * Lines 2..N+1: Input line i+1 describes building i with three space-separated integers: A_i, B_i, and H_i Output * Line 1: The total area,…

P2061 [USACO07OPEN]城市的地平线City Horizon 扫描线 扫描线简化版 流程(本题为例): 把一个矩形用两条线段(底端点的坐标,向上长度,添加$or$删除)表示,按横坐标排序 $upd:$本题的底端点坐标简化为$(x,0)$ 蓝后对纵坐标建一棵线段树(本题需要对高度进行离散化). 每次对线段树进行覆盖$or$删除区间操作,顺便统计一下$k=$有多少点被覆盖到 而两次(线段)操作之间的长度为$r=x_{i}-x_{i-1}$ 于是两条线段之间被覆盖的面积即为$k*r$ (…

[BZOJ1645][Usaco2007 Open]City Horizon 城市地平线 Description Farmer John has taken his cows on a trip to the city! As the sun sets, the cows gaze at the city horizon and observe the beautiful silhouettes formed by the rectangular buildings. The entire ho…

http://www.lydsy.com/JudgeOnline/problem.php?id=1645 这题的方法很奇妙啊...一开始我打了一个“离散”后的线段树.............果然爆了..(因为压根没离散) 这题我们可以画图知道,每2个点都有一个区间,而这个区间的高度是一样的,因此,我们只需要找相邻的两个点,用他们的距离×这个区间的高度就是这块矩形的面积. 将所有这样的矩形累计起来就是答案了. 因此线段树就离散到了O(n)的大小..真神.. 只需要维护点的位置,然后维护区间最值即可…

H. City Horizon Time Limit: 2000ms Memory Limit: 65536KB 64-bit integer IO format: %lld      Java class name: Main   Farmer John has taken his cows on a trip to the city! As the sun sets, the cows gaze at the city horizon and observe the beautiful si…