力扣181(MySQL)- 超过经理收入的员工（简单）

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181. 超过经理收入的员工 + join + MySql

181. 超过经理收入的员工 LeetCode_MySql_181 题目描述方法一:笛卡尔积 # Write your MySQL query statement below select e1.Name as 'Employee' from Employee e1, Employee e2 where e1.ManagerId = e2.Id and e1.Salary > e2.Salary; 方法二:join方法 # Write your MySQL query statement be…

LeetCode：181.超过经理收入的员工

sql 181. 超过经理收入的员工

Employee 表包含所有员工,他们的经理也属于员工.每个员工都有一个 Id,此外还有一列对应员工的经理的 Id. +----+-------+--------+-----------+| Id | Name | Salary | ManagerId |+----+-------+--------+-----------+| 1 | Joe | 70000 | 3 || 2 | Henry | 80000 | 4 || 3 | Sam | 60000 | NULL || 4 | Max | 9…

[LeetCode] 181.超过经理收入的员工

Employee表包含所有员工,他们的经理也属于员工.每个员工都有一个 Id,此外还有一列对应员工的经理的 Id. +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 | Joe | 70000 | 3 | | 2 | Henry | 80000 | 4 | | 3 | Sam | 60000 | NULL | | 4 | Ma…

LeetCode 181. Employees Earning More Than Their Managers (超过经理收入的员工)

题目标签: 题目给了我们一个员工表,包括经理.员工会有经理的id. 这里可以重复利用两次表格,表格a, 表格b,当a 员工的经理id 等于 b员工时候,在从中找到员工工资大于经理的.具体看code. Java Solution: Runtime: 312 ms, faster than 65 % Memory Usage: N/A 完成日期:05/22/2019 关键点:From 员工表a,b # Write your MySQL query statement below SELEC…

[SQL]LeetCode181. 超过经理收入的员工 | Employees Earning More Than Their Managers

SQL架构 Create table If Not Exists Employee (Id ), Salary int, ManagerId int) Truncate table Employee insert into Employee (Id, Name, Salary, ManagerId) values (') insert into Employee (Id, Name, Salary, ManagerId) values (') insert into Employee (Id,…

超过经理收入的员工表的自JOIN

https://leetcode-cn.com/problems/employees-earning-more-than-their-managers/description/ The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +----+-------+--------+…