537. 复数乘法 537. Complex Number Multiplication 题目描述 Given two strings representing two complex numbers. You need to return a string representing their multiplication. Note i2 = -1 according to the definition. LeetCode537. Complex Number Multiplication中…

Given two strings representing two complex numbers. You need to return a string representing their multiplication. Note i2 = -1 according to the definition. Example 1: Input: "1+1i", "1+1i" Output: "0+2i" Explanation: (1 + i)…

Given two strings representing two complex numbers. You need to return a string representing their multiplication. Note i2 = -1 according to the definition. Example 1: Input: "1+1i", "1+1i" Output: "0+2i" Explanation: (1 + i)…

537. 复数乘法 给定两个表示复数的字符串. 返回表示它们乘积的字符串.注意,根据定义 i2 = -1 . 示例 1: 输入: "1+1i", "1+1i" 输出: "0+2i" 解释: (1 + i) * (1 + i) = 1 + i2 + 2 * i = 2i ,你需要将它转换为 0+2i 的形式. 示例 2: 输入: "1±1i", "1±1i" 输出: "0±2i" 解释:…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 日期 题目地址:https://leetcode.com/problems/complex-number-multiplication/description/ 题目描述 Given two strings representing two complex numbers. You need to return a string representing th…

详见:https://leetcode.com/problems/complex-number-multiplication/description/ C++: class Solution { public: string complexNumberMultiply(string a, string b) { int n1 = a.size(), n2 = b.size(); auto p1 = a.find_last_of("+"), p2 = b.find_last_of(&qu…

Given two strings representing two complex numbers. You need to return a string representing their multiplication. Note i2 = -1 according to the definition. Example 1: Input: "1+1i", "1+1i" Output: "0+2i" Explanation: (1 + i)…

原题链接在这里:https://leetcode.com/problems/complex-number-multiplication/description/ 题目: Given two strings representing two complex numbers. You need to return a string representing their multiplication. Note i2 = -1 according to the definition. Example…

题目大意: 给出a, b两个用字符串表示的虚数,求a*b 题目思路: 偷了个懒,Python3的正则表达式匹配了一下,当然acm里肯定是不行的 class Solution: def complexNumberMultiply(self, a, b): """ :type a: str :type b: str :rtype: str """ match = re.search(r'([+-]*\d+)[+-]([+-]*\d+)i$', a)…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find >the two elements that a…