Given a string S, return the "reversed" string where all characters that are not a letter stay in the same place, and all letters reverse their positions. Example 1: Input: "ab-cd" Output: "dc-ba" Example 2: Input: "a-bC…
题目标签:String 利用left, right 两个pointers, 从左右开始 互换 字母.如果遇到的不是字母,那么继续移动到下一个. Java Solution: Runtime beats 29.87% 完成日期:12/08/2018 关键点:two pointers class Solution { public String reverseOnlyLetters(String S) { char[] charArr = S.toCharArray(); int left = 0;…
题目要求 Given a string S, return the "reversed" string where all characters that are not a letter stay in the same place, and all letters reverse their positions. 题目分析及思路 给定一个字符串,返回“reversed”后的字符串,要求非字母的字符保留原来的位置,字母字符逆序排列.可以先获得原字符串中的全部字母字符列表,然后遍历原字…
https://leetcode.com/problems/reverse-only-letters/ Given a string S, return the "reversed" string where all characters that are not a letter stay in the same place, and all letters reverse their positions.   Example 1: Input: "ab-cd"…
problem 917. Reverse Only Letters solution: class Solution { public: string reverseOnlyLetters(string S) { , j=S.size()-; i<j; )//err... { if(!isalpha(S[i])) i++; else if(!isalpha(S[j])) j--; else { char tmp = S[i]; S[i] = S[j]; S[j] = tmp; i++; j--;…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 栈 单指针 双指针 日期 题目地址: https://leetcode.com/contest/weekly-contest-105/problems/reverse-only-letters/ 题目描述 Given a string S, return the "reversed" string where all characters…
Given a string S, return the "reversed" string where all characters that are not a letter stay in the same place, and all letters reverse their positions.   Example 1: Input: "ab-cd" Output: "dc-ba" Example 2: Input: "a-…
Given a string s, reverse the string according to the following rules: All the characters that are not English letters remain in the same position. All the English letters (lowercase or uppercase) should be reversed. class Solution { public: string r…
对于链表的问题,根据以往的经验一般都是要建一个dummy node,连上原链表的头结点,这样的话就算头结点变动了,我们还可以通过dummy->next来获得新链表的头结点.这道题的要求是只通过一次遍历完成,就拿题目中的例子来说,变换的是2,3,4这三个点,我们需要找到第一个开始变换结点的前一个结点,只要让pre向后走m-1步即可,为啥要减1呢,因为题目中是从1开始计数的,这里只走了1步,就是结点1,用pre指向它.万一是结点1开始变换的怎么办,这就是我们为啥要用dummy结点了,pre也可以指向…
给定一个字符串 S,返回 "反转后的" 字符串,其中不是字母的字符都保留在原地,而所有字母的位置发生反转. 示例 1: 输入:"ab-cd" 输出:"dc-ba" 示例 2: 输入:"a-bC-dEf-ghIj" 输出:"j-Ih-gfE-dCba" 示例 3: 输入:"Test1ng-Leet=code-Q!" 输出:"Qedo1ct-eeLg=ntse-T!" 提…
Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up:If this function…
Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. Clarification: What constitutes a…
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters.The input string does not contain leading or trailing spaces and the words are always separated by a single space.For example,Given s = "t…
Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc"…
Write a function that takes a string as input and reverse only the vowels(元音字母) of a string. Example 1:Given s = "hello", return "holle". Example 2:Given s = "leetcode", return "leotcede". Note:The vowels does not i…
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3947 访问. 给定一个单词,你需要判断单词的大写使用是否正确. 我们定义,在以下情况时,单词的大写用法是正确的: 全部字母都是大写,比如"USA". 单词中所有字母都不是大写,比如"leetcode". 如果单词不只含有一个字母,只有首字母大写, 比如 "Google". 否则,我们定义这个单词没有正确使用大写字…
[LeetCode]848. Shifting Letters 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/shifting-letters/description/ 题目描述: We have a string S of lowercase letters, and an integer arr…
文本行的排序用到了命令行参数以及多级指针,在要求只对字母数字空格进行排序时,关键的问题点是兼容-f命令参数,也就是排序的同时忽略大小写.由于在之前的练习中,我将忽略大小写的比较方法重新写了一个函数transfercmp(),于是无法再sort排序程序中同时调用他们.因此,不得不增加一个外部变量uptolow,用来在只对字母数字排序的函数inpuntcmp()中兼容忽略大小写的排序方式.暂时还没有想到更好的方法. #include <stdio.h> #include <string.h&…
LeetCode 260. Single Number III(只出现一次的数字 III)…
LeetCode 137. Single Number II(只出现一次的数字 II)…
Leetcode 25. Reverse Nodes in k-Group 以每组k个结点进行链表反转(链表) 题目描述 已知一个链表,每次对k个节点进行反转,最后返回反转后的链表 测试样例 Input: k = 2, 1->2->3->4->5 Output: 2->1->4->3->5 Input: k = 3, 1->2->3->4->5 Output: 3->2->1->4->5 详细分析 按照题目要求…
Reverse a linked list from position m to n. Do it in one-pass. Note: 1 ≤ m ≤ n ≤ length of list. Example: Input: 1->2->3->4->5->NULL, m = 2, n = 4 Output: 1->4->3->2->5->NULL 这个题目是在[LeetCode] 206. Reverse Linked List_Easy tag…
LeetCode:反转字符串中的元音字母[345] 题目描述 编写一个函数,以字符串作为输入,反转该字符串中的元音字母. 示例 1: 输入: "hello" 输出: "holle" 示例 2: 输入: "leetcode" 输出: "leotcede" 说明:元音字母不包含字母"y". 题目分析 所谓的做题就是把以前背下来的拿过来改一下即可.双指针碰撞模型,之前已经描述过很多次了,此处不在赘述. 知道AEI…
Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2->5->NULL. Note: Given m, n satisfy the following condition: 1 ≤ m ≤ n ≤ le…
Python isalpha() 方法检测字符串是否只由字母组成.…
Reverse a linked list from position m to n. Do it in-place and in one-pass. For example:Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2->5->NULL. Note:Given m, n satisfy the following condition:1 ≤ m ≤ n ≤ lengt…
//假定输入的字符串只包含字母和*号,fun函数:除了尾部的*号以外,将字符的其他*号进行全部删除,形参p已经指向字符串中最后一个字母. #include <stdio.h> void fun( char *a, char *p ) { ];//肯定是要进行再定义的. ,j; q = a; while (*q) { if (q == p)//判断地址相等,进行返回 { break; } if ((*q >= 'a'&&*q <= 'z') || (*q >=…
这是悦乐书的第353次更新,第378篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第215题(顺位题号是917).给定一个字符串S,返回"反向"字符串,其中所有非字母的字符都保留在同一位置,并且所有字母都反转其位置.例如: 输入:"ab-cd" 输出:"dc-ba" 输入:"a-bC-dEf-ghIj" 输出:"j-Ih-gfE-dCba" 输入:"Test1ng-L…
Given a string S, return the "reversed" string where all characters that are not a letter stay in the same place, and all letters reverse their positions. Example 1: Input: "ab-cd" Output: "dc-ba" Example 2: Input: "a-bC…
Given an array nums, we call (i, j) an important reverse pair if i < j and nums[i] > 2*nums[j]. You need to return the number of important reverse pairs in the given array. Example1: Input: [1,3,2,3,1] Output: 2 Example2: Input: [2,4,3,5,1] Output:…