http://poj.org/problem?id=2187 题意:求凸包上最远点距离的平方 思路:开始用旋转卡壳求的最远点,WA,改了好久..后来又改成枚举凸包上的点..AC了.. #include <stdio.h> #include <algorithm> #include <math.h> using namespace std; ; int n; struct Point { int x,y; Point(,):x(x),y(y) {} bool friend…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 24283   Accepted: 7420 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bess…

/* poj 2187 Beauty Contest 凸包:寻找每两点之间距离的最大值 这个最大值一定是在凸包的边缘上的! 求凸包的算法: Andrew算法! */ #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; struct Point{ Point(){} Point(int x, int y){ this->…

题目链接 题意:给你n个点的坐标,n<=50000,求最远点对 #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <cmath> #include <vector> #include <queue> #include <map> #include <algorithm> #i…

Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 25256   Accepted: 7756 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a…

Beauty Contest http://poj.org/problem?id=2187 题目描述:输入n对整数点,求最距离远的点对,输出他们距离的平方和 算法:拿到这个题,最朴素的想法就是用2层循环遍历所有的点对,但这样可能会超时.由于距离最远的点对必定在点集的凸包的顶点上,所以只用遍历凸包上的点对就行.这样就把可能存在的大量的点给排除.哈哈~~~还是凸包. #include <iostream> #include <algorithm> #include <iomani…

题目链接:http://poj.org/problem?id=2187 Time Limit: 3000MS Memory Limit: 65536K Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 27276   Accepted: 8432 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bess…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 36113   Accepted: 11204 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bes…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 27507   Accepted: 8493 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bess…

链接:传送门 题意:给出 n 个点,求出这 n 个点中最远的两个点距离的平方 思路:最远点对一定会在凸包的顶点上,然后直接暴力找一下凸包顶点中距离最远的两个点 /************************************************************************* > File Name: poj2187.cpp > Author: WArobot > Blog: http://www.cnblogs.com/WArobot/ > Cre…

xuán zhuǎn qiǎ ké模板题 是这么读吧(≖ ‿ ≖)✧ 算法挺简单:找对踵点即可,顺便更新答案. #include<cstdio> #include<cstring> #include<algorithm> #define read(x) x=getint() #define max(a,b) (a)>(b)?(a):(b) #define N 50003 using namespace std; inline int getint() { int…

P1452 Beauty Contest 题意 求平面\(n(\le 50000)\)个点的最远点对 收获了一堆计算几何的卡点.. 凸包如果不保留共线的点,在加入上凸壳时搞一个相对栈顶,以免把\(n\)号点删走了 旋转卡壳和凸包都想一下更新的时候带不带等于号阿 Code: #include <cstdio> #include <algorithm> using std::max; const int N=5e4+10; int s[N],tot,n,p; struct Vector…

链接:http://poj.org/problem?id=2187 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of N (2 <= N <= 50,000) farms around the wor…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 26180   Accepted: 8081 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bess…

链接: http://poj.org/problem?id=2187 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=22013#problem/E Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 24254   Accepted: 7403 Description Bessie, Farmer John's prize cow, h…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 31414   Accepted: 9749 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bess…

Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of N (2 <= N <= 50,000) farms around the world in order to spread goodwill bet…

D - Beauty Contest Time Limit:3000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a r…

 凸包(旋转卡壳) 大概理解了凸包A了两道模板题之后在去吃饭的路上想了想什么叫旋转卡壳呢?回来无聊就搜了一下,结果发现其范围真广. 凸包: 凸包就是给定平面图上的一些点集(二维图包),然后求点集组成的凸多边形,但是要包含所有的点. 求凸多边形的方法:Graham算法描述如下: Graham()算法先对点进行排序,有极角序和水平序两种排序方式.我们仍然以左下方的点作为基准点来通过叉积进行排序.利用STL里面的sort或者自己写个排序算法,排序所用时间为O(NlogN),极角序列如左图所示:极角排序…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 24431   Accepted: 7459 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bess…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 38349   Accepted: 11851 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bes…

题面 Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of N (2 <= N <= 50,000) farms around the world in order to spread goodwill between farm…

Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of N (2 <= N <= 50,000) farms around the world in order to spread goodwill between farmers…

http://poj.org/problem?id=2187 题意 给n个坐标,求最远点对的距离平方值. 分析 模板题,旋转卡壳求求两点间距离平方的最大值. #include<iostream> #include<cmath> #include<cstring> #include<queue> #include<vector> #include<cstdio> #include<algorithm> #include<…

Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of N (2 <= N <= 50,000) farms around the world in order to spread goodwill bet…

转载请注明出处: http://www.cnblogs.com/fraud/          ——by fraud Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 31214   Accepted: 9681 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty con…

Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 32708   Accepted: 10156 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a…

Luogu 1452 Beauty Contest 求平面最远点对,先求出凸包,再找凸包的直径. 使用旋转卡壳,直径一定出现在对踵点对间.比较不同点到同一直线距离可以用叉积算三角形面积来比较. 实现时注意关于栈的 \(top\) 的细节. #include<bits/stdc++.h> using namespace std; #define ll long long #define mp make_pair #define pii pair<int,int> inline int…

原题如下: Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 42961   Accepted: 13307 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a resul…