POJ Fence Repair(优先队列)】的更多相关文章

Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 51346   Accepted: 16857 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…
poj 3253 Fence Repair 优先队列 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000) planks of wood, each having some integer length Li (1 ≤ Li ≤ 50,000) u…
Fence Repair Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000) planks of wood, each having some integer length Li (1 ≤ Li ≤ 50,000) units. He then purchases a…
Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 67319   Accepted: 22142 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…
题目链接:http://poj.org/problem?id=3253 思路分析:题目与哈夫曼编码原理相同,使用优先队列与贪心思想:读入数据在优先队列中,弹出两个数计算它们的和,再压入队列中: 代码如下: #include <iostream> #include <queue> using namespace std; struct cmp { bool operator() (long long a, long long b) { return a > b; } }; in…
题目链接:http://poj.org/problem?id=3253 题意:给出n块木板的长度L1,L2...Ln,求在一块总长为这个木板和的大木板中如何切割出这n块木板花费最少,花费就是将木板切割前的长度. 有个陷阱就是需要用long long 去储存 如 Sample Input 3 8 5 8 Sample Output 34 就是将一块长为21的木板先切成13和8,花费21.然后将13切成5和8,花费13,总花费21 + 13 = 34. 分析:如果考虑从一块木板分割成小木板,方法数会…
一个很长的英文背景,其他不说了,就是告诉你锯一个长度为多少的木板就要花多少的零钱,把一块足够长(不是无限长)的木板锯成n段,每段长度都告诉你了,让你求最小花费. 明显的huffman树,优先队列是个很好的东西. #include <stdio.h> #include <queue> #include <algorithm> #include <iostream> #include <vector> #define ll __int64 using…
由于,这两题有着似乎一样的解法所以将其放在一起总结比較,以达到更好的区分二者的差别所在. 一.区间DP uva的Cutting Sticks是一道典型的模板题. 题目描写叙述: 有一根长度为l的木棍,木棍上面有m个分割点,每一次分割都要付出当前木棍长度的代价,问如何分割有最小代价. 区间DP的定义: 区间动态规划问题一般都是考虑.对于每段区间,他们的最优值都是由几段更小区间的最优值得到,是分治思想的一种应用.将一个区间问题不断划分为更小的区间直至一个元素组成的区间,枚举他们的组合,求合并后的最优…
POJ 3253 Fence Repair (优先队列) Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needsN (1 ≤ N ≤ 20,000) planks of wood, each having some integer lengthLi (1 ≤ Li ≤ 50,000) units. He the…
Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 25274   Accepted: 8131 Description Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needs N (1 ≤ N ≤ 20,000)…