版权声明:来自: 码代码的猿猿的AC之路 http://blog.csdn.net/ck_boss https://blog.csdn.net/u012797220/article/details/35860567 JAVA大数.... Children's Queue Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 10390    …

Children’s Queue Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 17918    Accepted Submission(s): 5976 Problem Description There are many students in PHT School. One day, the headmaster whose na…

Problem Description There are many students in PHT School. One day, the headmaster whose name is PigHeader wanted all students stand in a line. He prescribed that girl can not be in single. In other words, either no girl in the queue or more than one…

递推,最近发现自己做递推的题总是没有思路.下周多练习.对于f(n)可以在第n个位置为男生,此时共有f(n-1)种情况:若在第n个位置为女生,因此第n-1个位置也必须为女生.此时有两种情况,一种情况是在f(n-2)后直接添加FF,另一种情况是在MF后添加FF将本来错误的串改为正确的,这种情况数量为f(n-4)(前n-4排列满足要求).因此,f(n) = f(n-1) + f(n-2) + f(n-4).题目数据超过64位,大数AC. #include <stdio.h> #include <…

这道题是排序问题,可以用递归方法解决. 计算F(n): 一:当最后一个是男孩M时候,前面n-1个随便排出来,只要符合规则就可以,即是F(n-1): 二:当最后一个是女孩F时候,第n-1个肯定是女孩F,这时候又有两种情况: 1)前面n-2个可以按n-2个的时候的规则来,完全可以,即是F(n-2): 2)但是即使前面n-2个人不是合法的队列,加上两个女生也有可能是合法的.当第n-2是女孩而n-3是男孩的情况,可能合法,情况总数为F(n-4); 综上所述:总数F(n)=F(n-1)+F(n-2)+F(…

Children’s Queue Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 12101 Accepted Submission(s): 3953 Problem Description There are many students in PHT School. One day, the headmaster whose name is…

Children’s Queue Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13333    Accepted Submission(s): 4364 Problem Description There are many students in PHT School. One day, the headmaster whose na…

Children's Queue Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 11117    Accepted Submission(s): 3577 Problem Description There are many students in PHT School. One day, the headmaster whose n…

Children's Queue Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 10040    Accepted Submission(s): 3198 Problem Description There are many students in PHT School. One day, the headmaster whose n…

Children’s Queue Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 16006    Accepted Submission(s): 5337 Problem Description There are many students in PHT School. One day, the headmaster whose n…