题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5115 Dire Wolf Time Limit: 5000/5000 MS (Java/Others)Memory Limit: 512000/512000 K (Java/Others) 问题描述 Dire wolves, also known as Dark wolves, are extraordinarily large and powerful wolves. Many, if not…

Dire wolves, also known as Dark wolves, are extraordinarily large and powerful wolves. Many, if not all, Dire Wolves appear to originate from Draenor. Dire wolves look like normal wolves, but these creatures are of nearly twice the size. These powerf…

Problem Description Dire wolves, also known as Dark wolves, are extraordinarily large and powerful wolves. Many, if not all, Dire Wolves appear to originate from Draenor. Dire wolves look like normal wolves, but these creatures are of nearly twice th…

Dire wolves, also known as Dark wolves, are extraordinarily large and powerful wolves. Many, if not all, Dire Wolves appear to originate from Draenor. Dire wolves look like normal wolves, but these creatures are of nearly twice the size. These powerf…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5115 题目分类:区间dp 题意:有n只狼,每只狼有两种属性,一种攻击力一种附加值,我们没杀一只狼,那么我们受到的伤害值为这只狼的攻击值与它旁边的两只狼的附加值的和,求把所有狼都杀光受到的最小的伤害值. 题目分析: dp[i][j]表示把区间i,j内的所有狼杀光所受到的最小的伤害. 状态转移方程为 dp[i][j]=min{dp[i][k]+dp[k+1][j]-b[k]+b[i+1], dp[i][…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5115 题目大意:有一些狼,从左到右排列,每只狼有一个伤害A,还有一个伤害B.杀死一只狼的时候,会受到这只狼的伤害A和这只狼两边的狼的伤害B的和.若两只狼之间的狼都被杀了,这两只狼也算相邻.求杀掉一排狼的最小代价.解题思路:设dp[i][j]为消灭编号从i到j只狼的代价,那么结果就是dp[1][n]枚举k作为最后一只被杀死的狼,此时会受到a[k]和b[i-1] b[j+1]的伤害 取最小的即可.可列出…

比赛的时候以为很难,其实就是一个区间DP= =..思路见:点我. 区间DP一定要记住先枚举区间长度啊= =~!因为区间dp都是由短的区间更新长的区间的,所以先把短的区间更新完.. 代码如下: #include <stdio.h> #include <algorithm> #include <string.h> using namespace std; + ; const int inf = 0x3f3f3f3f; int n; int a[N],b[N]; int dp…

考虑先枚举所有的物品中最后拿走的,这样就分成了2个子问题,即先拿完左边的,再拿完右边的,最后拿选出的那个.令dp(i,j)表示拿完[i,j]所有物品的最小代价.你可能会说,我们拿[i,j]这一段物品的时候,i左边和j右边的第一个物品可能会不断变化,影响i和j的最终价格.其实是不会的,还是想想一开始说的整个序列枚举最后被拿走的,然后不断分割成子问题的过程,我们都是先拿走[i,j]中的所有元素,之后才会去动i-1或者j+1.所以可以澄清一下dp状态含义:dp(i,j)表示原序列中把[i,j]中的元素…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5115 题目大意:前面有n头狼并列排成一排, 每一头狼都有两个属性--基础攻击力和buff加成, 每一头狼的攻击力等于他自身的基础攻击力加上旁边狼对他的buff加成. 现在你被这群狼围着了, 必须将这些狼全部击败, 你才能逃出, 你每攻击一头狼,收到的伤害是狼的总攻击力.现在问,你逃出这些狼的围攻需要的最小代价(收到的伤害): 解题思路:声明dp数组, dp[i][j]代表从i到j的区间杀死所有狼的最…

Dire Wolf Time Limit: 5000/5000 MS (Java/Others)    Memory Limit: 512000/512000 K (Java/Others)Total Submission(s): 3815    Accepted Submission(s): 2266 Problem Description Dire wolves, also known as Dark wolves, are extraordinarily large and powerfu…