题目大意:给一个偶数,判断是否是两个素数的和. 先用sieve方法生成一个素数表,然后再进行判断即可. #include <cstdio> #include <vector> #include <bitset> using namespace std; typedef vector<int> vi; typedef long long ll; #define MAXN 1000000 vi primes; bitset<MAXN+> bs; vo…

给你一个n求出n由2个奇质因子的和  这2个因子差最大 没有就输出'Goldbach's conjecture is wrong. #include<stdio.h> #include<string.h> #include<algorithm> #include<vector> #include<math.h> using namespace std; #define MAXN 1000010 bool pri[MAXN]; int main()…

 Goldbach's Conjecture Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Description In 1742, Christian Goldbach, a German amateur mathematician, sent a letter to Leonhard Euler in which he made the following…

1.Link: http://poj.org/problem?id=2262 http://bailian.openjudge.cn/practice/2262 2.Content: Goldbach's Conjecture Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 37791   Accepted: 14536 Description In 1742, Christian Goldbach, a German a…

http://poj.org/problem?id=2262 Goldbach's Conjecture Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 34323   Accepted: 13169 Description In 1742, Christian Goldbach, a German amateur mathematician, sent a letter to Leonhard Euler in whic…

Problem Description Goldbach's Conjecture: For any even number n greater than or equal to 4, there exists at least one pair of prime numbers p1 and p2 such that n = p1 + p2. This conjecture has not been proved nor refused yet. No one is sure whether…

Goldbach's Conjecture Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5277    Accepted Submission(s): 2022点我 Problem Description Goldbach's Conjecture: For any even number n greater than or equa…

[LightOJ1259]Goldbach`s Conjecture(数论) 题面 Vjudge T组询问,每组询问是一个偶数n 验证哥德巴赫猜想 回答n=a+b 且a,b(a<=b)是质数的方案个数 题解 筛出质数后直接暴力判断就行了 质数密度没有那么大,记得节约空间 #include<iostream> #include<cstdio> #include<cstdlib> #include<cstring> #include<cmath>…

题目链接: https://cn.vjudge.net/problem/POJ-2262 题目描述: In 1742, Christian Goldbach, a German amateur mathematician, sent a letter to Leonhard Euler in which he made the following conjecture: Every even number greater than 4 can be written as the sum of t…

题目链接:http://ac.jobdu.com/problem.php?pid=1440 详解链接:https://github.com/zpfbuaa/JobduInCPlusPlus 参考代码: // // 1440 Goldbach's Conjecture.cpp // Jobdu // // Created by PengFei_Zheng on 12/04/2017. // Copyright © 2017 PengFei_Zheng. All rights reserved. /…

Goldbach`s Conjecture Goldbach's conjecture is one of the oldest unsolved problems in number theory and in all of mathematics. It states: Every even integer, greater than 2, can be expressed as the sum of two primes [1]. Now your task is to check whe…

poj2262 Goldbach's Conjecture 用欧拉筛把素数筛出来,再枚举一下. #include<iostream> #include<cstdio> #include<cstring> #define re register using namespace std; #define N 1000001 int n,v[N],pri[N],cct; bool is[N]; int main(){ ;i<N;++i){ ; ;j<=cct;++…

题目描述 Goldbach's Conjecture: For any even number n greater than or equal to 4, there exists at least one pair of prime numbers p1 and p2 such that n = p1 + p2. This conjecture has not been proved nor refused yet. No one is sure whether this conjecture…

/** 题目:F - Goldbach`s Conjecture 链接:https://vjudge.net/contest/154246#problem/F 题意:对一个大于2的偶数n,找有多少种方法使两个素数的和为n:保证素数a<=b; a+b==n; a,b都为素数. 思路:直接暴力,为了避免内存超限,用bool类型判断素数. */ #include<bits/stdc++.h> using namespace std; typedef long long ll; ; bool f…

题目:http://poj.org/problem?id=2262 大水题的筛质数. #include<iostream> #include<cstdio> #include<cstring> using namespace std; const int N=1e6; ],cnt; ]; void init() { ;i<=N;i++) { if(!vis[i])pri[++cnt]=i; ;j<=cnt&&(long long)i*pri[…

一.Description In 1742, Christian Goldbach, a German amateur mathematician, sent a letter to Leonhard Euler in which he made the following conjecture: Every even number greater than 4 can be written as the sum of two odd prime numbers. For example: 8…

In 1742, Christian Goldbach, a German amateur mathematician, sent a letter to Leonhard Euler in which he made the following conjecture: Every even number greater than 4 can be written as the sum of two odd prime numbers. For example: 8 = 3 + 5. Both…

题目链接:https://vjudge.net/problem/LightOJ-1259 1259 - Goldbach`s Conjecture    PDF (English) Statistics Forum Time Limit: 2 second(s) Memory Limit: 32 MB Goldbach's conjecture is one of the oldest unsolved problems in number theory and in all of mathem…

                                                                                1259 - Goldbach`s Conjecture 分拆素数和,本来很水的题,但硬生生跪了18+.这题卡内存实在太凶残了,MLT了10+,TLE了10+. 题意:在1e7内验证哥德巴赫猜想,求一个数拆分成两个不同的素数和有多少中方法. 思路:打表.就是打表. 但为什么会MLE呢,因为1e7的数组实在太大了,于是换了好几种写法优化,但…

Goldbach's conjecture is one of the oldest unsolved problems in number theory and in all of mathematics. It states: Every even integer, greater than 2, can be expressed as the sum of two primes [1]. Now your task is to check whether this conjecture h…

Goldbach's Conjecture Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 48161   Accepted: 18300 Description In 1742, Christian Goldbach, a German amateur mathematician, sent a letter to Leonhard Euler in which he made the following conject…

Goldbach`s Conjecture(LightOJ - 1259)[简单数论][筛法] 标签: 入门讲座题解 数论 题目描述 Goldbach's conjecture is one of the oldest unsolved problems in number theory and in all of mathematics. It states: Every even integer, greater than 2, can be expressed as the sum of…

[题目描述] 原题来自:Ulm Local,题面详见:POJ 2262 哥德巴赫猜想:任何大于 44 的偶数都可以拆成两个奇素数之和. 比如: 8=3+5 20=3+17=7+13 42=5+37=11+31=13+29=19+23 你的任务是:验证小于 106 的数满足哥德巴赫猜想. [输入] 多组数据,每组数据一个 n. 读入以 0 结束. [输出] 对于每组数据,输出形如 n=a+b,其中 a,b 是奇素数.若有多组满足条件的 a,b,输出 b−a 最大的一组. 若无解,输出 Goldba…

链接: https://vjudge.net/problem/LightOJ-1259 题意: Goldbach's conjecture is one of the oldest unsolved problems in number theory and in all of mathematics. It states: Every even integer, greater than 2, can be expressed as the sum of two primes [1]. Now…

For any even number n greater than or equal to 4, there exists at least one pair of prime numbers p1 and p2 such that n = p1 + p2 This conjecture has not been proved nor refused yet. No one is sure whether this conjecture actually holds. However, one…

题目链接:http://poj.org/problem?id=2262 哥德巴赫猜想肯定是正确的 思路: 筛出n范围内的所有奇质数,对每组数据试过一遍即可, 为满足b-a取最大,a取最小 时空复杂度分析: 在1e6内约有8e4个奇质数,因为a <= b,时间复杂度在T*4e4+1e6等级.一般T为1e3,足以承受 空间复杂度为1e6,足以承受 #include <cstdio> #include <cstring> #include <algorithm> usi…

题目意思很简单,就是找n=p1+p2的种类数,具体看题目吧. 次重点是查找一定范围内的素数: 重点是用二分查找,不然会超时!!! #include<stdio.h> #include<string.h> int main() { ],num,s,l,r,mid; a[]=;s=; ;i<;i=i+)//这里是打出素数 { f=; ;j<s;j++) { if(a[j]*a[j]>i) break; ) { f=; break; } } ) a[s++]=i; }…

http://lightoj.com/volume_showproblem.php?problem=1259 题目大意:给你一个数n,这个数能分成两个素数a.b,n = a + b且a<=b,问有几组这样的(a,b) 比较简单的哥德巴赫猜想题,不需要多说,但一般的素数判定会TLE,所以这里用的是素数筛选法 这里需要注意的是筛选出来素数数组的大小 #include<stdio.h> #include<math.h> #include<string.h> #inclu…

题意:给出n,问满足a+b=n且a,b都为素数的有多少对 将素数打表,再枚举 #include<iostream> #include<cstdio> #include<cstring> #include <cmath> #include<stack> #include<vector> #include<map> #include<algorithm> #define mod=1e9+7; using names…

不想说了 #include <cstdio> #include <iostream> #include <ctime> #include <vector> #include <cmath> #include <map> #include <queue> #include <algorithm> #include <cstring> using namespace std; typedef long…