cf Strings of Power】的更多相关文章

http://codeforces.com/contest/318/problem/B #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; ]; int main() { cin>>str; int k=strlen(str); __int64 t=,ans=; ; i<k; i++) { ]==…
B. Strings of Power Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/318/problem/B Description Volodya likes listening to heavy metal and (occasionally) reading. No wonder Volodya is especially interested in texts concerning…
B. Strings of Power Volodya likes listening to heavy metal and (occasionally) reading. No wonder Volodya is especially interested in texts concerning his favourite music style. Volodya calls a string powerful if it starts with "heavy" and ends w…
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B. Strings of Power Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/318/problem/C Description Let us call a pair of integer numbers m-perfect, if at least one number in the pair is greater than or equal to m. Thus, the pair…
A. Even Odds 奇数个数\(\lfloor \frac{n+1}{2}\rfloor\) B. Strings of Power 从位置0开始,统计heavy个数,若当前为metal,则可以和之前的所有heavy配对. C. Perfect Pair 假设\(x\le y\),显然用\(x+y\)替换\(x\)可以达到最少步数. \(x\)会一直\(+y\)直到\(x'\gt y\). D. Ants 暴力模拟??? E. Balance 构出一棵树后,就随便做了. F. Game w…
Power Strings Time Limit: 3000MSMemory Limit: 65536K Total Submissions: 29663Accepted: 12387 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef…
F - Power Strings Time Limit:3000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 2406 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = &…
Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 30069   Accepted: 12553 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…
Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 41252   Accepted: 17152 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…
E - Power Strings Time Limit:3000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 2406 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = &…
点击打开链接 Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 27368   Accepted: 11454 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b =…
http://poj.org/problem?id=2406 Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 27003   Accepted: 11311 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = &q…
Power Strings Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponentiation by a non…
Power Strings TimeLimit: 1 Second   MemoryLimit: 32 Megabyte Totalsubmit: 1791   Accepted: 528 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcd…
Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 36926   Accepted: 15254 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…
Power Strings Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 39291 Accepted: 16315 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcd…
Power Strings Time Limit : 6000/3000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 29   Accepted Submission(s) : 14 Problem Description Given two strings a and b we define a*b to be their concatenation. For example,…
Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 28102   Accepted: 11755 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…
Language: Default Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 33205   Accepted: 13804 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def"…
Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 29402   Accepted: 12296 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…
Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 45008   Accepted: 18794 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…
Description Problem D: Power Strings Given two strings a and b we define a*b to be their concatenation. For example, ifa = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponentiatio…
UVA10298 Power Strings hash+乘法逆元+一点点数学知识 我们用取余法算出主串的hash,然后从小到大枚举子串的长度 显然,如果若干个子串的复制的hash值之和等于主串的hash值,那么答案就得到了. 然后我们计算子串(设子串长度为 i )的hash值: hash=t*(+base^i+base^2i+...+base^(len-i)) 如果直接暴力求,那么显然会TLE 于是我们进行推导: 设: Si=+base^i+base^2i+...+base^(len-i) S=…
链接: http://poj.org/problem?id=2406 Power Strings Time Limit:3000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc&qu…
题目传送门 Power Strings 格式难调,题面就不放了. 一句话题意,求给定的若干字符串的最短循环节循环次数. 输入样例#1: abcd aaaa ababab . 输出样例#1: 1 4 3 就这样. 分析: 一道思路神奇的题目,需要深入理解$KMP$的$next$数组. 如果自己写几个字符串推一下就可以发现,一个由循环节构成的字符串,从第二个循环节开始$next$值是依次递增的,因为$next$数组的本质是表示$0\~i-1$的最长公共前缀后缀长度.也就不难想到,只要判断一下$nex…
Power Strings Problem's Link: http://poj.org/problem?id=2406 Mean: 给你一个字符串,让你求这个字符串最多能够被表示成最小循环节重复多少次得到. analyse: KMP之next数组的运用.裸的求最小循环节. Time complexity: O(N) Source code:  ;;      ;);      ) ;}/* */…
                                                                                                  Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 38038   Accepted: 15740 Description Given two strings a and b we define a*b t…
poj2406 Power Strings(kmp) 给出一个字符串,问这个字符串是一个字符串重复几次.要求最大化重复次数. 若当前字符串为S,用kmp匹配'\0'+S和S即可. #include <cstdio> #include <cstring> using namespace std; const int maxn=2e6+5; char s1[maxn], s2[maxn]; int n1, n2, nxt[maxn], ans; int main(){ while (~…
Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 28859   Accepted: 12045 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…