Max Num---hdu2071】的更多相关文章

JSU省赛队员选拔赛个人赛1 一.题目概述: A.Coin Change(暴力求解.动态规划)     B.Fibbonacci Number(递推求解) C.Max Num(排序.比较) D.单词数(字符串比较.库函数运用) E.无限的路(平面几何) F.叠筐(规律输出) 二.解题报告: A.Coin Change 给一个钱的总金额,求出用100个以内的50分.25分.10分.5分.1分硬币拼成该金额的不同拼法. 直接暴力,打表什么的都是浮云.开始总觉得用暴力求解显得自己没风度,不够高端霸气上…
Problem Description There are some students in a class, Can you help teacher find the highest student . Input There are some cases. The first line contains an integer t, indicate the cases; Each case have an integer n ( 1 ≤ n ≤ 100 ) , followed n stu…
Problem Description There are some students in a class, Can you help teacher find the highest student .   Input There are some cases. The first line contains an integer t, indicate the cases; Each case have an integer n ( 1 ≤ n ≤ 100 ) , followed n s…
http://acm.hdu.edu.cn/showproblem.php?pid=2071 Problem Description There are some students in a class, Can you help teacher find the highest student .   Input There are some cases. The first line contains an integer t, indicate the cases; Each case h…
Max Num Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 16818    Accepted Submission(s): 10381 Problem Description There are some students in a class, Can you help teacher find the highest stude…
http://acm.hdu.edu.cn/showproblem.php?pid=1003 给出一个包含n个数字的序列{a1,a2,..,ai,..,an},-1000<=ai<=1000 求最大连续子段和及其起始位置和终止位置,很基础的动态规划(DP)问题,看完DP第一次做的DP题目 DP真的是一种很优美的算法,或者说思想,但是比较难理解,我对DP的理解还很浅薄 # include <stdio.h> # define INF 1000000000 int main() { i…
Max Sum Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 135262    Accepted Submission(s): 31311 Problem Description Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max s…
This question is the same as "Max Chunks to Make Sorted" except the integers of the given array are not necessarily distinct, the input array could be up to length 2000, and the elements could be up to 10**8. Given an array arr of integers (not…
Given an array arr that is a permutation of [0, 1, ..., arr.length - 1], we split the array into some number of "chunks" (partitions), and individually sort each chunk.  After concatenating them, the result equals the sorted array. What is the m…
那个数所在类型中,x的幂最大值为max 1.则第一条判定:max%num==0: 若x不为任何数的幂,则第一条判定足矣. 若x为某个数的幂,则要加判定条件 2.(num-1)%(x-1)==0 同时满足这两个条件的num,必然为x的幂. 第二个条件可以用数学来证明,把num写成一堆x相乘,拿去除以(x-1),分子添项,一项一项除,最后必然没有余数.…