求出平面图的对偶图,那么需要选择一些环,使得这些环可以异或出所有环. 对于两个不同的区域,需要用一个代价最小的环把它们区分开,这对应最小割. 那么求出对偶图的最小割树,所有树边之和就是把所有区域都区分开的最小代价. #include<cstdio> #include<cmath> #include<set> #include<algorithm> #include<map> using namespace std; typedef pair<…

A - Pattern String 留坑. B - Bazinga 题意:找一个最大的i,使得前i - 1个字符串中至少不是它的子串 思路:暴力找,如果有一个串已经符合条件,就不用往上更新 #include <bits/stdc++.h> using namespace std; #define N 510 int t, n; int vis[N]; string s[N]; int main() { ios::sync_with_stdio(false); int t; cin >&…

P2735 电网 Electric Fences 11通过 28提交 题目提供者该用户不存在 标签USACO 难度普及/提高- 提交  讨论  题解 最新讨论 暂时没有讨论 题目描述 在本题中,格点是指横纵坐标皆为整数的点. 为了圈养他的牛,农夫约翰(Farmer John)建造了一个三角形的电网.他从原点(0,0)牵出一根通电的电线,连接格点(n,m)(0<=n<32000,0<m<32000),再连接格点(p,0)(p>0),最后回到原点. 牛可以在不碰到电网的情况下被放…

P2731 骑马修栅栏 Riding the Fences• o 119通过o 468提交• 题目提供者该用户不存在• 标签USACO• 难度普及+/提高 提交 讨论 题解 最新讨论 • 数据有问题题目背景Farmer John每年有很多栅栏要修理.他总是骑着马穿过每一个栅栏并修复它破损的地方.题目描述John是一个与其他农民一样懒的人.他讨厌骑马,因此从来不两次经过一个栅栏.你必须编一个程序,读入栅栏网络的描述,并计算出一条修栅栏的路径,使每个栅栏都恰好被经过一次.John能从任何一个顶点(即…

Electric Fences Kolstad & Schrijvers Farmer John has decided to construct electric fences. He has fenced his fields into a number of bizarre shapes and now must find the optimal place to locate the electrical supply to each of the fences. A single wi…

Riding the Fences Farmer John owns a large number of fences that must be repaired annually. He traverses the fences by riding a horse along each and every one of them (and nowhere else) and fixing the broken parts. Farmer John is as lazy as the next…

Best Cow Fences Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 14601 Accepted: 4720 Description Farmer John's farm consists of a long row of N (1 <= N <= 100,000)fields. Each field contains a certain number of cows, 1 <= ncows <= 2…

Best Cow Fences Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 10174 Accepted: 3294 Description Farmer John's farm consists of a long row of N (1 <= N <= 100,000)fields. Each field contains a certain number of cows, 1 <= ncows <= 2…

P2731 骑马修栅栏 Riding the Fences 题目背景 Farmer John每年有很多栅栏要修理.他总是骑着马穿过每一个栅栏并修复它破损的地方. 题目描述 John是一个与其他农民一样懒的人.他讨厌骑马,因此从来不两次经过一个栅栏.你必须编一个程序,读入栅栏网络的描述,并计算出一条修栅栏的路径,使每个栅栏都恰好被经过一次.John能从任何一个顶点(即两个栅栏的交点)开始骑马,在任意一个顶点结束. 每一个栅栏连接两个顶点,顶点用1到500标号(虽然有的农场并没有500个顶点).一个…

Electric FencesKolstad & Schrijvers Farmer John has decided to construct electric fences. He has fenced his fields into a number of bizarre shapes and now must find the optimal place to locate the electrical supply to each of the fences. A single wir…

P2731 骑马修栅栏 Riding the Fences 题目背景 Farmer John每年有很多栅栏要修理.他总是骑着马穿过每一个栅栏并修复它破损的地方. 题目描述 John是一个与其他农民一样懒的人.他讨厌骑马,因此从来不两次经过一个栅栏.你必须编一个程序,读入栅栏网络的描述,并计算出一条修栅栏的路径,使每个栅栏都恰好被经过一次.John能从任何一个顶点(即两个栅栏的交点)开始骑马,在任意一个顶点结束. 每一个栅栏连接两个顶点,顶点用1到500标号(虽然有的农场并没有500个顶点).一个…

题目链接:https://vjudge.net/problem/POJ-2018 Best Cow Fences Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 11394   Accepted: 3736 Description Farmer John's farm consists of a long row of N (1 <= N <= 100,000)fields. Each field contains a…

Riding the Fences Farmer John owns a large number of fences that must be repairedannually. He traverses the fences by riding a horse along each andevery one of them (and nowhere else) and fixing the broken parts. Farmer John is as lazy as the next fa…

Best Cow Fences Time Limit: 1000MS Memory Limit: 30000K Description Farmer John's farm consists of a long row of N (1 <= N <= 100,000)fields. Each field contains a certain number of cows, 1 <= ncows <= 2000. FJ wants to build a fence around a…

破解Linux的用户密码:John [跨平台的密码解密工具] root@only:~# unshadow /etc/passwd /etc/shadow > ~/file_to_crack root@only:~# john --wordlist=/usr/share/john/password.lst ~/file_to_crack   rm -fr /root/.john/john.pot unshadow p s >file john --wordlist=zidian.txt file…

John Problem Description   Little John is playing very funny game with his younger brother. There is one big box filled with M&Ms of different colors. At first John has to eat several M&Ms of the same color. Then his opponent has to make a turn. A…

题目描述 在本题中,格点是指横纵坐标皆为整数的点. 为了圈养他的牛,农夫约翰(Farmer John)建造了一个三角形的电网.他从原点(0,0)牵出一根通电的电线,连接格点(n,m)(0<=n<32000,0<m<32000),再连接格点(p,0)(p>0),最后回到原点. 牛可以在不碰到电网的情况下被放到电网内部的每一个格点上(十分瘦的牛).如果一个格点碰到了电网,牛绝对不可以被放到该格点之上(或许Farmer John会有一些收获).那么有多少头牛可以被放到农夫约翰的电网…

函数:split() 功能:使用一个指定的分隔符把一个字符串分割存储到数组例子: var theString=”jpg|bmp|gif|ico|png”; var arr=theString.split(”|”); //arr是一个包含字符值”jpg”.”bmp”.”gif”.”ico”和”png”的数组 函数:John() 功能:使用您选择的分隔符将一个数组合并为一个字符串例子: var delimitedString=myArray.join(delimiter); var myList=n…

John the RipperJohn the Ripper(简称John)是一款著名的密码破解工具.它主要针对各种Hash加密的密文.它不同于Rainbow Table方式.它采用实时运算的方式和密文进行比较.为了提高运行效率,它提供各种辅助功能.例如,它提供辅助工具unshadow收集用户名等相关信息,内置了海量的常用密码,预编译了大量的Mangling Rule.针对用户需求,它提供了三种模式,应对不同的场景需求.例如,Single crack(单一破解)模式用于弱密码场景:Wordlis…

Description John is the only priest in his town. September 1st is the John's busiest day in a year because there is an old legend in the town that the couple who get married on that day will be forever blessed by the God of Love. This year N couples…

Description 小约翰经常和他的哥哥玩一个非常有趣的游戏:桌子上有n堆石子,小约翰和他的哥哥轮流取石子,每个人取 的时候,可以随意选择一堆石子,在这堆石子中取走任意多的石子,但不能一粒石子也不取,我们规定取到最后一 粒石子的人算输.小约翰相当固执,他坚持认为先取的人有很大的优势,所以他总是先取石子,而他的哥哥就聪明 多了,他从来没有在游戏中犯过错误.小约翰一怒之前请你来做他的参谋.自然,你应该先写一个程序,预测一下 谁将获得游戏的胜利. Input 本题的输入由多组数据组成第一行包括一个…

Description Little John is playing very funny game with his younger brother. There is one big box filled with M&Ms of different colors. At first John has to eat several M&Ms of the same color. Then his opponent has to make a turn. And so on. Pleas…

对于任意一个 Anti-SG 游戏,如果我们规定当局面中所有的单一游戏的 SG 值为 0 时,游戏结束,则先手必胜当且仅当:  (1)游戏的 SG 函数不为 0 且游戏中某个单一游戏的 SG 函数大于 1:(2)游戏的 SG 函数为 0 且游戏中没有单一游戏的 SG 函数大于 1. John Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s):…

fences:  http://www.jb51.net/softs/309746.html http://jingyan.baidu.com/article/e8cdb32b6e958337042bad5d.html eDiary: http://www.onlinedown.net/soft/176049.htm…

Priest John's Busiest Day Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1420    Accepted Submission(s): 415 Problem Description John is the only priest in his town. October 26th is the John's…

题目背景 Farmer John每年有很多栅栏要修理.他总是骑着马穿过每一个栅栏并修复它破损的地方. 题目描述 John是一个与其他农民一样懒的人.他讨厌骑马,因此从来不两次经过一个栅栏.你必须编一个程序,读入栅栏网络的描述,并计算出一条修栅栏的路径,使每个栅栏都恰好被经过一次.John能从任何一个顶点(即两个栅栏的交点)开始骑马,在任意一个顶点结束. 每一个栅栏连接两个顶点,顶点用1到500标号(虽然有的农场并没有500个顶点).一个顶点上可连接任意多(>=1)个栅栏.两顶点间可能有多个栅栏.…

参见上一篇博客,里面有分析和结论. #include <cstdio> int main() { int T; scanf("%d", &T); while(T--) { , xorsum = ;//c为充裕堆的个数 scanf("%d", &n); ) c++; } ) || (xorsum && !c)) puts("Brother");//T2和S0状态必败 else puts("Joh…

题意:有N场婚礼,每场婚礼的开始时间为Si,结束时间为Ti,每场婚礼有个仪式,历时Di,这个仪式要么在Si时刻开始,要么在Ti-Di时刻开始,问能否安排每场婚礼举行仪式的时间,使主持人John能参加所有的这些仪式的全过程. 题目链接:http://poj.org/problem?id=3683 ——>>每场婚礼的仪式,要么在开始段举行,要么在结束段举行,且一定要举行,要求各场婚礼仪式没冲突——>>2-SAT... 2-SAT挺神,针对此类问题,可谓手到擒来... LJ<训练指…

博弈论 一看题,哇这不是Nim游戏么= =直接异或起来……啊咧怎么不对? 这道题是[Anti-Nim],普通的Nim是取走最后一个就赢,这题是取走最后一个输…… 做法参见 2009年贾志豪论文<组合游戏略述——浅谈SG游戏的若干拓展及变形> /************************************************************** Problem: 1022 User: Tunix Language: C++ Result: Accepted Time:16…

Saint John Festival 题目链接: http://acm.hust.edu.cn/vjudge/contest/127406#problem/J Description Porto's Festa de São João is one of Europe's liveliest street festivals. Its peak is the night of 23rd to 24th of June, with dancing parties from Ribeira to…