1002 A+B for Polynomials (25)(25 分) This time, you are supposed to find A+B where A and B are two polynomials. Input Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 a~N1…

1002. A+B for Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue This time, you are supposed to find A+B where A and B are two polynomials. Input Each input file contains one test case. Each case occupies 2 lines, an…

This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​​​ N​2​​ a​N​2​…

题意: 给出两个多项式,计算两个多项式的积,并以指数从大到小输出多项式的指数个数,指数和系数. trick: 这道题数据未知,导致测试的时候发现不了问题所在. 用set统计非零项时,通过set.size()输出非零项个数,set.count()与否来判断是否输出该项时结果第0个测试点答案错误. 用fabs(mp[i])>=0.05时结果全部正确,因为考虑到保留1位小数所以用这个语句来判断保留小数后是否非零. 问题是当去掉fabs()时采用mp[i]>=0.05结果第0个测试点答案错误. 而不管…

PAT (Advanced Level) Practice 1002 A+B for Polynomials (25 分) 凌宸1642 题目描述: This time, you are supposed to find A+B where A and B are two polynomials. 译:这一次,你要找到 A + B ,其中 A , B 是两个多项式 Input Specification (输入说明): Each input file contains one test case…

PAT甲级:1036 Boys vs Girls (25分) 题干 This time you are asked to tell the difference between the lowest grade of all the male students and the highest grade of all the female students. Input Specification: Each input file contains one test case. Each cas…

PAT甲级:1089 Insert or Merge (25分) 题干 According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the loca…

1002. A+B for Polynomials (25) This time, you are supposed to find A+B where A and B are two polynomials. Input Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN…

1002 A+B for Polynomials (25 分) This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial…

1145 Hashing - Average Search Time (25 分)   The task of this problem is simple: insert a sequence of distinct positive integers into a hash table first. Then try to find another sequence of integer keys from the table and output the average search ti…

1066 Root of AVL Tree (25 分)   An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child subtrees of any node differ by at most one; if at any time they differ by more than one, rebalancing is done to restore th…

1055 The World's Richest (25 分)   Forbes magazine publishes every year its list of billionaires based on the annual ranking of the world's wealthiest people. Now you are supposed to simulate this job, but concentrate only on the people in a certain r…

1047 Student List for Course (25 分)   Zhejiang University has 40,000 students and provides 2,500 courses. Now given the registered course list of each student, you are supposed to output the student name lists of all the courses. Input Specification:…

1039 Course List for Student (25 分)   Zhejiang University has 40000 students and provides 2500 courses. Now given the student name lists of all the courses, you are supposed to output the registered course list for each student who comes for a query.…

题意:给出两个多项式,计算两个多项式的和,并以指数从大到小输出多项式的指数个数,指数和系数. AAAAAccepted code: #include<bits/stdc++.h> using namespace std; ]; int main(){ int k; cin>>k; ; ;i<=k;++i){ int n; cin>>n; double x; cin>>x; a[n]+=x; max_n=max(max_n,n); } cin>&g…

题目描述: This time, you are supposed to find A+B where A and B are two polynomials. Input Each input file contains one test lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, , , ..., K) are the exponents and coef…

https://pintia.cn/problem-sets/994805342720868352/problems/994805526272000000 This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each…

PATA1002 A+B for Polynomials This time, you are supposed to find A+B where A and B are two polynomials. Sample Input: 2 1 2.4 0 3.2 2 2 1.5 1 0.5 Sample Output: 3 2 1.5 1 2.9 0 3.2 #include<cstdio> #include<iostream> using namespace std; int m…

题目 This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​ ​​ N​2​​ a​…

题意: 输入一个正整数N(<=20),代表结点个数(0~N-1),接着输入N行每行包括每个结点的左右子结点,'-'表示无该子结点,输出是否是一颗完全二叉树,是的话输出最后一个子结点否则输出根节点. trick: 用char输入子结点没有考虑两位数的结点…

题意: 输入一个正整数N(<=100),接着输入两个浮点数(可能包含前导零,对于PAT已经习惯以string输入了,这点未知),在保留N位有效数字的同时判断两个数是否相等,并以科学计数法输出. trick: 测试点3含有有效数字在小数点以后的数据,此时指数应该是小数点位置减有效数字位置再加上1. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; stri…

This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​​​ N​2​​ a​N​2​…

题意: 输入一个正整数N(<=10000),接着输入N行数字每行包括一个正整数K和K个正整数,表示这K只鸟是同一棵树上的.输出最多可能有几棵树以及一共有多少只鸟.接着输入一个正整数Q,接着输入Q行每行包括两个正整数,输出它们是否在同一棵树上. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; ]; int find_(int x){ if(x==f…

题意: 输入一个正整数N(2<=N<=1e5),接着输入N个正整数,将这些数字划分为两个不相交的集合,使得他们的元素个数差绝对值最小且元素和差绝对值最大. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL…

题意: 输入两个正整数N和M(N<100,M<N),表示结点数量和有孩子结点的结点数量,输出拥有结点最多的层的结点数量和层号(根节点为01,层数为1,层号向下递增). AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; vector<]; ]; void dfs(int x,int storey){ ++ans[storey]; for(aut…

题意: 输入一个正整数N(<=100),接着输入两行N个整数,第一行表示初始序列,第二行表示经过一定程度的排序后的序列.输出这个序列是由插入排序或者归并排序得到的,并且下一行输出经过再一次排序操作所得到的序列.数据保证了不会有两种排序方式都可以得到的序列. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; ]; int main(){ ios::s…

题意:输入一个正整数N(<=30),接着输入2*N行表示栈的出入(入栈顺序表示了二叉搜索树的先序序列,出栈顺序表示了二叉搜索树的中序序列),输出后序序列. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; stack<int>st; ],b[]; ]; void build(int n,int*a,int*b,int*ans){ if(!n)…

题意: 输入链表头结点的地址(五位的字符串)和两个正整数N和K(N<=100000,K<=N),接着输入N行数据,每行包括结点的地址,结点的数据和下一个结点的地址.输出每K个结点局部反转的链表. trick: 测试点6包含一些不在起点这条链表上的结点. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; map<string,pair<i…

题意: 输入三个正整数N,L,H(N<=1E5,L>=60,H<100,H>L),分别代表人数,及格线和高水平线.接着输入N行数据,每行包括一个人的ID,道德数值和才能数值.一个人的道德和才能都不低于H时为圣人,道德不低于H才能不低于L时为贵族,道德和才能都不低于L且道德不低于才能时为愚者,道德和才能都不低于L且道德低于才能时为小人(圣人优先判断,圣人的才能可以高于道德).分别在自己的所在的群体内排序,依照道德才能总和降序排序,第二优先为才能的数值降序,第三优先为id的升序.按照题…

题意: 输入两个正整数N和M(<=1000),接着输入两行,每行N个数,第一行为每只老鼠的重量,第二行为每只老鼠出战的顺序.输出它们的名次.(按照出战顺序每M只老鼠分为一组,剩余不足M只为一组,每组只能有一个胜者,其他老鼠排名均为这一轮胜者数量+1) AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; int n,m; ],b[]; int num; ];…