Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. For example, given n = 12, return 3 because 12 = 4 + 4 + 4; given n = 13, return 2 because 13 = 4 + 9. 题目大意:给一个正整数,找出可以由最少个平方数…
原题链接在这里:https://leetcode.com/problems/perfect-squares/ 题目: Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. For example, given n = 12, return 3 because 12 = 4 + 4 + 4; given n…
原文地址 https://www.jianshu.com/p/2925f4d7511b 迫于就业的压力,不得不先放下 iOS 开发的学习,开始走上漫漫刷题路. 今天我想聊聊 LeetCode 上的第279题-Perfect Squares,花了挺长时间的,试了很多方法,作为一个算法新手,个人感觉这题很好,对我的水平提升很有帮助.我在这里和大家分享一下我的想法.下面是题目: Given a positive integer n, find the least number of perfect s…
题目 Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. 给定正整数 n,找到若干个完全平方数(比如 1, 4, 9, 16, ...)使得它们的和等于 n.你需要让组成和的完全平方数的个数最少. Example 1: Input: n = 12 Output: 3 Explanation: 12 =…
Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. ExampleGiven n = 12, return 3 because 12 = 4 + 4 + 4Given n = 13, return 2 because 13 = 4 + 9 LeetCode上的原题,请参见我之前的博客Perfect Sq…
Perfect Squares Total Accepted: 18854 Total Submissions: 63048 Difficulty: Medium Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. For example, given n = 12, return 3 because …
