LintCode: Fizz Buzz】的更多相关文章

C++ class Solution { public: /** * param n: As description. * return: A list of strings. */ vector<string> fizzBuzz(int n) { vector<string> results; ; i <= n; i++) { == ) { results.push_back("fizz buzz"); } == ) { results.push_bac…
------------------------ AC代码: class Solution { /** * param n: As description. * return: A list of strings. */ public ArrayList<String> fizzBuzz(int n) { ArrayList<String> results = new ArrayList<String>(); for (int i = 1; i <= n; i++…
下面是AC代码,C++风格: class Solution { public: vector<string> fizzBuzz(int N) { vector<string> Answer; ;i <= N;i++) { == ) { Answer.push_back("fizz buzz"); } == ) { Answer.push_back("fizz"); } == ) { Answer.push_back("buzz…
题目来源:http://www.lintcode.com/zh-cn/problem/fizz-buzz/…
Write a program that outputs the string representation of numbers from 1 to n. But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and fiv…
Problem: Write a program that outputs the string representation of numbers from 1 to n. But for multiples of three it should output "Fizz" instead of the number and for the multiples of five output "Buzz". For numbers which are multipl…
原题链接在这里:https://leetcode.com/problems/fizz-buzz/ 题目: Write a program that outputs the string representation of numbers from 1 to n. But for multiples of three it should output "Fizz" instead of the number and for the multiples of five output &qu…
class Solution { public: /** * param n: As description. * return: A list of strings. */ vector<string> fizzBuzz(int n) { vector<string> results; ; i <= n; i++) { == ) { results.push_back("fizz buzz"); } == ) { results.push_back(&q…
写一段程序从1打印到100,但是遇到3的倍数时打印Fizz,遇到5的倍数时打印Buzz,遇到即是3的倍数同时也是5的倍数时打印FizzBuzz.例如: 1 2 Fizz 4 Buzz Fizz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz 16 17 Fizz 19 Buzz ... 等等,直到 100…
看到一篇文章上说,很多貌似看过很多本编程书的童鞋连简单的fizz buzz测试都完不成. 不知道fizz buzz test为何物的,建议自行搜之. 测试要求是,编写满足以下条件的代码: Write a program that prints the numbers from 1 to 100. But for multiples of three print "Fizz" instead of the number which are multiples of both three…
Write a program that outputs the string representation of numbers from 1 to n. But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and fiv…
在CSDN上看到一篇文章<软件工程师如何笑着活下去>,本来是想看对这个行业的一些评价和信息,不曾检索到关于Fizz Buzz的面试题,上网搜了一下,顿感兴趣.留下此文,以表回忆. java语言 小白基础写法: public class FizzBuzz {    public static void main(String[] args) {        for (int i = 1; i <= 100; i++) {                                  …
这是悦乐书的第221次更新,第233篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第88题(顺位题号是412). 编写一个程序,输出从1到n的数字的字符串表示.但对于三的倍数,它应输出"Fizz"而不是数字,对于五的倍数,应该输出"Buzz". 对于三和五共同的倍数,应输出"FizzBuzz".例如: 输入:n = 15 输出:["1","2","Fizz"…
Description Given number n. Print number from 1 to n. But: when number is divided by 3, print "fizz". when number is divided by 5, print "buzz". when number is divided by both 3 and 5, print "fizz buzz". Example If n = 15, yo…
problem 412. Fizz Buzz solution: class Solution { public: vector<string> fizzBuzz(int n) { vector<string> res; ; i<=n;++i) { != &&(i%!=)) res.push_back(to_string(i)); ==) res.push_back("FizzBuzz"); ==) res.push_back("…
写一个程序,输出从 1 到 n 数字的字符串表示. 如果 n 是3的倍数,输出"Fizz": 如果 n 是5的倍数,输出"Buzz": 3.如果 n 同时是3和5的倍数,输出 "FizzBuzz". 示例: n = 15, 返回: [ "1", "2", "Fizz", "4", "Buzz", "Fizz", "7&…
写一个程序,输出从 1 到 n 数字的字符串表示. 如果 n 是3的倍数,输出"Fizz": 如果 n 是5的倍数,输出"Buzz": 3.如果 n 同时是3和5的倍数,输出 "FizzBuzz". 示例: n = 15, 返回: [ "1", "2", "Fizz", "4", "Buzz", "Fizz", "7&…
要求: 给你一个整数n. 从 1 到 n 按照下面的规则打印每个数: 如果这个数被3整除,打印fizz. 如果这个数被5整除,打印buzz. 如果这个数能同时被3和5整除,打印fizz buzz. 示例: 比如 n = 15, 返回一个字符串数组: [ "1", "2", "fizz", "4", "buzz", "fizz", "7", "8",…
Write a program that outputs the string representation of numbers from 1 to n. But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and fiv…
题目: 写一个程序,输出从 到 n 数字的字符串表示. . 如果 n 是3的倍数,输出“Fizz”: . 如果 n 是5的倍数,输出“Buzz”: .如果 n 同时是3和5的倍数,输出 “FizzBuzz”. 示例: n = , 返回: [ ", ", "Fizz", ", "Buzz", "Fizz", ", ", "Fizz", "Buzz", &quo…
LeetCode--Fizz Buzz Question Write a program that outputs the string representation of numbers from 1 to n. But for multiples of three it should output "Fizz" instead of the number and for the multiples of five output "Buzz". For numbe…
题目: Write a program that outputs the string representation of numbers from 1 to n. But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and…
写一个程序,输出从 1 到 n 数字的字符串表示. 1. 如果 n 是3的倍数,输出“Fizz”: 2. 如果 n 是5的倍数,输出“Buzz”: 3.如果 n 同时是3和5的倍数,输出 “FizzBuzz”. 示例: n = 15, 返回: [ "1", "2", "Fizz", "4", "Buzz", "Fizz", "7", "8", &q…
412. Fizz Buzz Easy Write a program that outputs the string representation of numbers from 1 to n. But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples o…
Write a program that outputs the string representation of numbers from 1 to n. But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and fiv…
提出问题 一个网友的博客,记录他在一次面试时,碰到面试官要求他在白板上用TensorFlow写一个简单的网络实现异或(XOR)功能.这个本身并不难,单层感知器不能解决异或问题是学习神经网络中的一个常识,而简单的两层神经网络却能将其轻易解决.但这个问题的难处在于,我们接触TensorFlow通常直接拿来写CNN,或者其他的深度学习相关的网络了,而实现这种简单网络,基本上从未做过:更何况,要求在白板上写出来,如果想bug free,并不是容易的事儿啊. 数据 李宏毅老师对数据进行了如下分析 对数字1…
mycode  99.06% class Solution(object): def fizzBuzz(self, n): """ :type n: int :rtype: List[str] """ ops = ['Fizz','Buzz','FizzBuzz'] res = [] for i in range(n): k = i + 1 if k%3 == 0 and k%5 == 0: res.append(ops[2]) elif k%3…
1. Keras Demo2 前节的Keras Demo代码: import numpy as np from keras.models import Sequential from keras.layers.core import Dense,Dropout,Activation from keras.optimizers import SGD,Adam from keras.utils import np_utils from keras.datasets import mnist def…
412. Fizz Buzz 写一个程序,输出从 1 到 n 数字的字符串表示. 如果 n 是3的倍数,输出"Fizz": 如果 n 是5的倍数,输出"Buzz": 3.如果 n 同时是3和5的倍数,输出 "FizzBuzz". 示例: n = 15, 返回: [ "1", "2", "Fizz", "4", "Buzz", "Fizz&…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目大意 解题方法 方法一:遍历判断 方法二:字符串相加 方法三:字典 日期 [LeetCode] https://leetcode.com/problems/fizz-buzz/ Total Accepted: 31093 Total Submissions: 53272 Difficulty: Easy ##Question Write a program that outp…