POJ 1260 Pearls 简单dp】的更多相关文章

1.POJ 1260 2.链接:http://poj.org/problem?id=1260 3.总结:不太懂dp,看了题解 http://www.cnblogs.com/lyy289065406/archive/2011/07/31/2122652.html 题意:珍珠,给出需求,单价,要求用最少的钱就可以买到相同数量的,相同(或更高)质量的珍珠. 把握题意,1.输入时,后输入的珍珠价格一定比前面输入的要贵.2.用高质量珍珠替代低质量. #include<iostream> #include…
题目:http://poj.org/problem?id=1260 题意:给出几类珍珠,以及它们的单价,要求用最少的钱就可以买到相同数量的,相同(或更高)质量的珍珠. 珍珠的替代必须是连续的,不能跳跃替代(这个不难证明,因为假如用第i+2类去替代第i类珍珠,会使最终的支付价格降低,那么用第i+1类去替代第i类珍珠会使最终的支付价格更加低) #include<iostream> #include<cstdio> #include<cstring> #include<…
Pearls Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 10558   Accepted: 5489 Description In Pearlania everybody is fond of pearls. One company, called The Royal Pearl, produces a lot of jewelry with pearls in it. The Royal Pearl has its…
思路: 直接DP也能做,这里用斜率DP. dp[i] = min{ dp[j] + ( sum[i] - sum[j] + 10 )*pr[i]} ; k<j<i  =>  dp[j] - dp[k] <pr[i]*( sum[j] - sum[k] ) 再套模板 #include<queue> #include<cstring> #include<set> #include<map> #include<stack> #i…
这个题目数据量很小,但是满足斜率优化的条件,可以用斜率优化dp来做. 要注意的地方,0也是一个决策点. #include <iostream> #include <cstdio> #include <cstring> using namespace std; const int maxn=1e2+9; int dp[maxn]; int a[maxn],p[maxn],sum[maxn]; int que[maxn]; bool chk1(int i,int j,int…
Pearls Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 6670 Accepted: 3248 Description In Pearlania everybody is fond of pearls. One company, called The Royal Pearl, produces a lot of jewelry with pearls in it. The Royal Pearl has its name…
Pearls Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 7210 Accepted: 3543 Description In Pearlania everybody is fond of pearls. One company, called The Royal Pearl, produces a lot of jewelry with pearls in it. The Royal Pearl has its name…
http://poj.org/problem?id=1260 Pearls Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 8474   Accepted: 4236 Description In Pearlania everybody is fond of pearls. One company, called The Royal Pearl, produces a lot of jewelry with pearls…
题意:给你n种花,m个盆,花盆是有顺序的,每种花只能插一个花盘i,下一种花的只能插i<j的花盘,现在给出价值,求最大价值 简单dp #include <iostream> #include<cstdio> #include<cstring> using namespace std; #define N 110 int dp[N][N],a[N][N]; int main(int argc, char** argv) { int n,m,i,j; while(sca…
Longest Ordered Subsequence 搬中文 Descriptions: 给出一个序列,求出这个序列的最长上升子序列. 序列A的上升子序列B定义如下: B为A的子序列 B为严格递增序列 Input 第一行包含一个整数n,表示给出序列的元素个数. 第二行包含n个整数,代表这个序列. 1 <= N <= 1000 Output 输出给出序列的最长子序列的长度. Sample Input 7 1 7 3 5 9 4 8 Sample Output 4 题目链接: https://v…