Given a binary tree, return all root-to-leaf paths. For example, given the following binary tree: 1 / \ 2 3 \ 5 All root-to-leaf paths are: ["1->2->5", "1->3"] 题目标签:Tree 这道题目给了我们一个二叉树,让我们记录所有的路径,返回一个array string list. 我们可以另外设一…

Given a binary tree, return all root-to-leaf paths. For example, given the following binary tree: 1 / \ 2 3 \ 5 All root-to-leaf paths are: ["1->2->5", "1->3"] 给一个二叉树,返回所有根到叶节点的路径. Java: /** * Definition for a binary tree node…

257. 二叉树的所有路径 给定一个二叉树,返回所有从根节点到叶子节点的路径. 说明: 叶子节点是指没有子节点的节点. 示例: 输入: 1 / \ 2 3 \ 5 输出: ["1->2->5", "1->3"] 解释: 所有根节点到叶子节点的路径为: 1->2->5, 1->3 /** * Definition for a binary tree node. * public class TreeNode { * int val;…

Given a binary tree, return all root-to-leaf paths. For example, given the following binary tree: 1 / \ 2 3 \ 5 All root-to-leaf paths are: ["1->2->5", "1->3"] 本题可以用DFS或者BFS. 解法一: DFS,参考自九章算法 class Solution: # @param {TreeNode…

查找二叉树中根节点到叶子节点的所有路径: 本题有两种解法:递归解法和非递归解法,递归解法请参考:http://blog.csdn.net/booirror/article/details/47733175 该博主对递归算法的讲解不多,但是代码还是很容易看懂的. 刚刚又看到了一个代码写的更好.更简洁的版本,这个版本应该是我看到的所有递归解法中代码最简洁的一个版本,学习了.网址为:http://www.2cto.com/kf/201601/456116.html 非递归解法如下: 1.设置一个二维数…

找到所有根到叶子的路径 深度优先搜索(DFS), 即二叉树的先序遍历. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<string> v…

Given a binary tree, return all root-to-leaf paths. For example, given the following binary tree: 1 / \ 2 3 \ 5 All root-to-leaf paths are: ["1->2->5", "1->3"] 思想:递归代码如下: /** * Definition for a binary tree node. * public class…

题目描述: Given a binary tree, return all root-to-leaf paths. For example, given the following binary tree: 1 / \ 2 3 \ 5 All root-to-leaf paths are: ["1->2->5", "1->3"] 解题思路: 使用递归法. 代码如下: /** * Definition for a binary tree node.…

题目: 给定一个二叉树,返回所有从根节点到叶子节点的路径. 说明: 叶子节点是指没有子节点的节点. 示例: 输入: 1 / \ 2 3 \ 5 输出: ["1->2->5", "1->3"] 解释: 所有根节点到叶子节点的路径为: 1->2->5, 1->3 解题思路: 递归,在参数列表里回溯的方法灰常好用,这里介绍两种方法. 代码: 法一: /** * Definition for a binary tree node. * s…

Given a binary tree, return all root-to-leaf paths. Note: A leaf is a node with no children. Example: Input: 1 / \ 2 3 \ 5 Output: ["1->2->5", "1->3"] Explanation: All root-to-leaf paths are: 1->2->5, 1->3 思路为DFS, 只是a…