UVa11995  I Can Guess the Data Structure! 思路:边读边模拟,注意empty的判断! 代码如下: #include<iostream> #include<queue> #include<stack> using namespace std; int main(){ queue<int> q; priority_queue<int> pri_q; stack<int> sta; int n; wh…

11995 - I Can Guess the Data Structure! There is a bag-like data structure, supporting two operations:1 x Throw an element x into the bag.2 Take out an element from the bag.Given a sequence of operations with return values, you’re going to guess the…

思路 简单题,用栈,队列,优先队列直接模拟即可 代码 #include <cstdio> #include <algorithm> #include <cstring> #include <queue> #include <stack> using namespace std; queue<int> q; stack<int> S; priority_queue<int> pq; int n; int main…

Implement a data structure supporting the following operations: Inc(Key) - Inserts a new key with value 1. Or increments an existing key by 1. Key is guaranteed to be a non-empty string. Dec(Key) - If Key's value is 1, remove it from the data structu…

I Can Guess the Data Structure! There is a bag-like data structure, supporting two operations: 1 x Throw an element x into the bag. 2 Take out an element from the bag. Given a sequence of operations with return values, you're going to guess the data…

常用数据结构及复杂度 http://www.cnblogs.com/gaochundong/p/3813252.html 常用数据结构的时间复杂度 Data Structure Add Find Delete GetByIndex  Array (T[]) O(n) O(n) O(n) O(1)  Linked list (LinkedList<T>) O(1) O(n) O(n) O(n)  Resizable array list (List<T>) O(1) O(n) O(n…

UVAlive 3135 Argus Argus Time Limit: 3000MS   Memory Limit: Unknown   64bit IO Format: %lld & %llu Submit Status Description A data stream is a real-time, continuous, ordered sequence of items. Some examples include sensor data, Internet traffic, fin…

UVa11991 Easy Problem from Rujia Liu?  思路:  构造数组data,使满足data[v][k]为第k个v的下标.因为不是每一个整数都会出现因此用到map,又因为每个数出现次数不等可能相差很大,因此用到vector. 注意:对于数据的清空与判空不要忘记,而map在调用之前必须有map.count的检查. 代码: #include<cstdio> #include<map> #include<vector> using namespac…

范围最小值问题: 提供操作: Query(L,R):计算min{AL ~ AR } Sparse-Table算法: 定义d[i][j]为从i开始长度为2j的一段元素的最小值.所以可以用递推的方法表示. 预处理RMQ_init如下(感觉像区间DP): int RMQ_init(const vector<int>& A){ int n=A.size(); ;i<n;i++) d[i][] = A[i]; ;(<<j)<=n;j++) ;i+(<<j)-&…

UVAlive 3026 Period 题目: Period   Time Limit: 3000MS   Memory Limit: Unknown   64bit IO Format: %lld & %llu Submit Status Description For each prefix of a given string S with N characters (each character has an ASCII code between 97 and 126, inclusive…