【动态规划】POJ2385-Apple Catching】的更多相关文章

                                            $Apple~Catching$ Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 16248   Accepted: 8009 $Description$ It is a little known fact that cows love apples. Farmer John has two apple trees (which are…
题目传送门 Apple Catching Apple Catching Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 15444   Accepted: 7582 Description It is a little known fact that cows love apples. Farmer John has two apple trees (which are conveniently numbered 1 an…
Description It is a little known fact that cows love apples. Farmer John has two apple trees (which are conveniently numbered 1 and 2) in his field, each full of apples. Bessie cannot reach the apples when they are on the tree, so she must wait for t…
https://vjudge.net/problem/POJ-2385 猛刷简单dp的第一天的第一题. 状态:dp[i][j]表示第i秒移动j次所得的最大苹果数.关键要想到移动j次,根据j的奇偶判断人在哪里. 想了挺久的,最后还是参考了一篇和自己思路最近的代码https://blog.csdn.net/hellohelloc/article/details/52050207 我比他缺少的是特判dp[i][0]的状态,后面的一切都以此为基础的. #include<iostream> #inclu…
思路: 简单dp. 实现: #include <iostream> #include <cstdio> #include <cstring> using namespace std; ]; ][][]; int dfs(int now,int cur,int rem) { ) return dp[now][cur][rem]; if(now == t) ; ,cur,rem) + (cur == x[now] - ); ) p = max(p, dfs(now, - c…
Apple Catching 直接翻译了 Descriptions 有两棵APP树,编号为1,2.每一秒,这两棵APP树中的其中一棵会掉一个APP.每一秒,你可以选择在当前APP树下接APP,或者迅速移动到另外一棵APP树下接APP(移动时间可以忽略不计),但由于却乏锻炼,你最多移动W次.问在T秒内,你最多能收集多少个APP.假设你开始站在1号APP树下. Input 第1行:两个整数T(1 < = T< = 1000)和W(1 < = W< = 30)第2..T+1行:1或2,代…
Apple Catching Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9978   Accepted: 4839 Description It is a little known fact that cows love apples. Farmer John has two apple trees (which are conveniently numbered 1 and 2) in his field, eac…
Apple Catching Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9831   Accepted: 4779 Description It is a little known fact that cows love apples. Farmer John has two apple trees (which are conveniently numbered 1 and 2) in his field, eac…
dp dp( x , k ) = max( dp( x - 1 , k - 1 ) + *** , dp( x - 1 , k ) + *** ) *** = 0 or 1 ,根据情况 (BZOJ 1750双倍经验) ------------------------------------------------------------------------ #include<cstdio> #include<cstring> #include<algorithm>…
3384/1750: [Usaco2004 Nov]Apple Catching 接苹果 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 18  Solved: 16[Submit][Status][Discuss] Description     很少有人知道奶牛爱吃苹果.农夫约翰的农场上有两棵苹果树(编号为1和2),每一棵树上都长满了苹果.奶牛贝茜无法摘下树上的苹果,所以她只能等待苹果从树上落下.但是,由于苹果掉到地上会摔烂,贝茜必须在半空中接住…