[LeetCode] Two Sum II - Input array is sorted 两数之和之二 - 输入数组有序

【[LeetCode] Two Sum II - Input array is sorted 两数之和之二 - 输入数组有序】的更多相关文章

[LeetCode] Two Sum II - Input array is sorted 两数之和之二 - 输入数组有序

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.The function twoSum should return indices of the two numbers such that they add up to the target, where index1 mu…

167 Two Sum II - Input array is sorted 两数之和 II - 输入有序数组

给定一个已按照升序排列的有序数组,找到两个数使得它们相加之和等于目标数.函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2.请注意,返回的下标值(index1 和 index2)不是从零开始的.你可以假设每个输入都只有一个解决方案,而且你不会重复使用相同的元素.输入:数组 = {2, 7, 11, 15}, 目标数 = 9输出:index1 = 1, index2 = 2详见:https://leetcode.com/problems/two-…

167. Two Sum II - Input array is sorted两数之和

1. 原始题目给定一个已按照升序排列的有序数组,找到两个数使得它们相加之和等于目标数. 函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2. 说明: 返回的下标值(index1 和 index2)不是从零开始的. 你可以假设每个输入只对应唯一的答案,而且你不可以重复使用相同的元素. 示例: 输入: numbers = [2, 7, 11, 15], target = 9 输出: [1,2] 解释: 2 与 7 之和等于目标数 9 .因此 in…

[LeetCode] 167. Two Sum II - Input array is sorted 两数和 II - 输入是有序的数组

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 m…

[LeetCode] Two Sum IV - Input is a BST 两数之和之四 - 输入是二叉搜索树

Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: True Example 2: Input: 5 / \ 3 6 / \ \ 2 4…