QSC and Master Problem Description   Every school has some legends, Northeastern University is the same. Enter from the north gate of Northeastern University,You are facing the main building of Northeastern University.Ninety-nine percent of the stude…

题目链接   http://acm.hdu.edu.cn/showproblem.php?pid=5900 题意:给出序列$A_{i}.key$和$A_{i}.value$,若当前相邻的两个数$A_{i}.key$和$A_{i+1}.key$的最大公约数大于1,则可以把这两个数消去,同时消去$A_{i}.value$和$A_{i+1}.value$,每次消去得到的分数为$A_{i}$和$A_{i+1}$的value值,问最大可能得分. 注意:当$A_{i}$和$A_{i+1}被$消去后,$A_{…

题意: 给n件物品,有key和value 每次可以把相邻的 GCD(key[i], key[i+1]) != 1 的两件物品,问移除的物品的总value最多是多少 key : 1 3 4 2  移除34以后12也相邻了,可以移除 分析: 先预处理出所有GCD[l][r], 意味 l <= i <= r的区域可以全部移除, 用记忆化搜索处理 然后 dp[i] 代表到 i 为止可以得到的最大value和 if (G[l][r]) dp[r] = max(dp[r], dp[l-1] + sum[r…

题目链接:传送门 题目大意:长度为n的key数组与value数组,若相邻的key互斥,则可以删去这两个数同时获得对应的两 个value值,问最多能获得多少 题目思路:区间DP 闲谈: 这个题一开始没有做出来,找了下原因,是自己思维太局限(刷题太少),始终想怎样去维护相 邻这个条件,删去数之后怎么来拼接左右两段...最后导致没解出来.. 正解: 其实维护拼接我们可以用一个数组来实现,先预处理原数组中相邻的两个数,然后再利用区间 DP思想来进行扩展,最后根据这个预处理好的数组来实现判断与更新. #i…

QSC and Master Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 859    Accepted Submission(s): 325 Problem Description Every school has some legends, Northeastern University is the same. Enter…

QSC and Master Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 612    Accepted Submission(s): 214 Problem Description Every school has some legends, Northeastern University is the same. Enter…

QSC and Master Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Problem Description Every school has some legends, Northeastern University is the same. Enter from the north gate of Northeastern University,You are…

题目 Source http://acm.hdu.edu.cn/showproblem.php?pid=5900 Description Every school has some legends, Northeastern University is the same. Enter from the north gate of Northeastern University,You are facing the main building of Northeastern University.…

题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=5900 Problem Description Every school has some legends, Northeastern University is the same. Enter from the north gate of Northeastern University,You are facing the main building of Northeastern Universi…

题意:给你n对pair 里面有两个值,分别是key 和 val .你可以取相邻的两个pair 获得其中的val,前提是两个pair 的key 的 gcd 不为 1.当然你把相邻的两个取走了之后原本不相邻的两个就变得相邻了.比如:你将下标为 2,3 取走之后,下标1,4就变得相邻了,求你可以获得的最大val. 题解:典型的合并问题,应该能想到用区间dp,但这里得考虑清楚,状态怎么转移.我们定义dp[i][j]为i~j能够获取的最大值.那么怎么更新状态呢,我们用一个前缀和去维护val,如果 dp[i…