题目如下: 解题思路:就三个字-线段树.这个题目是线段树用法最经典的场景. 代码如下: class NumArray(object): def __init__(self, nums): """ :type nums: List[int] """ self.nl = nums self.tree = [] if len(nums) == 0: return for i in xrange((4*len(nums)+1)): self.tree.a…
Range Sum Query - Mutable Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRa…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 预先求和 相似题目 参考资料 日期 题目地址:https://leetcode.com/problems/range-sum-query-2d-immutable/description/ 题目描述 Given a 2D matrix matrix, find the sum of the elements inside the rectangle…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 保存累积和 日期 题目地址:https://leetcode.com/problems/range-sum-query-immutable/description/ 题目描述 Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), in…
Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRange(0, 2) -> 9 update(1, 2…
Range Sum Query 2D - Immutable Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2). The above rectangle (with the red border) is defined by (row…
一. 题目描写叙述 Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRange(0, 2) -> 9 u…
题目: Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRange(0, 2) -> 9 update(…
Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRange(0, 2) -> 9 update(1, 2…
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