Talent Show】的更多相关文章

具体以源码为准 Talent继承自Marionette继承自BackBone Region: 继承自Backbone.Event,show(view)会调用view.render(),然后$el.append(view.el),触发相应的事件 Layout: 继承自 ItemView,可以设置regions属性 CompositeView: 继承自collectionView,将Item添加到template中 'itemview:deleteItem'事件 itemViewOptions Co…
/* L (>=60), the lower bound of the qualified grades -- that is, only the ones whose grades of talent and virtue are both not below this line will be ranked; and H (<100), the higher line of qualification ,those with both grades not below this line…
难得的一次ac 题目意思直接,方法就是对virtue talent得分进行判断其归属类型,用0 1 2 3 4 表示 不合格 sage noblemen foolmen foolmen 再对序列进行排序 优先级  类型>total grade>virtue>id #include<iostream> #include<stdio.h> #include<string.h> #include<algorithm> using namespac…
1. 在排序的过程中,注意边界的处理(小于.小于等于) 2. 对于B-level,这题是比較麻烦一些了. 源代码: #include <cstdio> #include <vector> #include <algorithm> using namespace std; struct People { int m_id; int m_virtue; int m_talent; People(int id, int virtue, int talent): m_id(id…
分数规划是这样一个东西: 给定若干元素,每个元素有两个属性值\(a_i,b_i\),在满足题目要求的某些限制下选择若干元素并求出\(\frac{\sum a}{\sum b}\)的最大值. 如果没有限制的话,肯定是贪心的选. 假设当前选择了一个解\(x_0\),却并不是\(\frac{\sum a}{\sum b}\)的最大值,我们有 \[\frac{\sum a}{\sum b}>x_0\] 进而 \[\sum a-bx_0>0\] 这时候我们要求的东西变成了\(a-bx_0\),每个元素的…
About 900 years ago, a Chinese philosopher Sima Guang wrote a history book in which he talked about people's talent and virtue. According to his theory, a man being outstanding in both talent and virtue must be a "sage(圣人)"; being less excellent…
Cocos2d-X开发教程-捕鱼达人 Cocos2-x development tutorial - fishing talent 作者:韩梦飞沙 Author:han_meng_fei_sha 邮箱:313134555@qq.com E-mail: 313134555 @qq.com 视频目录及链接:Video directory and links: 1 Cocos2D-X介绍  12:29  2 Cocos2D-X游戏安装过程和创建项目  10:14  3 Cocos2D-X启动流程-OC…
5281: [Usaco2018 Open]Talent Show Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 79  Solved: 58[Submit][Status][Discuss] Description FarmerJohn要带着他的N头奶牛,方便起见编号为1…N,到农业展览会上去,参加每年的达牛秀!他的第i头奶牛重量为wi,才艺水平为ti,两者都是整数.在到达时,FarmerJohn就被今年达牛秀的新规则吓到了:   (一)参加比…
[BZOJ5281]Talent Show(分数规划) 题面 BZOJ 洛谷 题解 二分答案直接就是裸的分数规划,直接跑背包判断是否可行即可. #include<iostream> #include<cstdio> using namespace std; #define ll long long #define MAX 255 inline int read() { int x=0;bool t=false;char ch=getchar(); while((ch<'0'|…
1062 Talent and Virtue (25 分) About 900 years ago, a Chinese philosopher Sima Guang wrote a history book in which he talked about people's talent and virtue. According to his theory, a man being outstanding in both talent and virtue must be a "sage(圣…