HDU - 1973 - Prime Path (BFS)】的更多相关文章

Prime Path Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 987    Accepted Submission(s): 635 Problem Description The ministers of the cabinet were quite upset by the message from the Chief of S…
Prime Path Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 21   Accepted Submission(s) : 18 Problem Description The ministers of the cabinet were quite upset by the message from the Chief of Sec…
Prime Path 原文是English 这里直接上中文了 Descriptions: 给你两个四位的素数a,b.a可以改变某一位上的数字变成c,但只有当c也是四位的素数时才能进行这种改变.请你计算a最少经过多少次上述变换才能变成b.例如:1033 -> 8179 1033 1733 3733 3739 3779 8779 8179最少变换了6次.Input 第一行输入整数T,表示样例数. (T <= 100) 每个样例输入两个四位的素数a,b.(没有前导零) Output 对于每个样例,输…
题目传送门  Prime Path The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-digit room numbers on their offices. — It is a matter of security to change such things ever…
题意为给出两个四位素数A.B,每次只能对A的某一位数字进行修改,使它成为另一个四位的素数,问最少经过多少操作,能使A变到B.可以直接进行BFS搜索 #include<bits/stdc++.h> using namespace std; bool isPrime(int n){//素数判断 || n == ) return true; else{ ; ; i < k; i++){ ) return false; } return true; } } ]; ]; void getPrime…
[题目链接]click here~~ [题目大意]给你n,m各自是素数,求由n到m变化的步骤数,规定每一步仅仅能改变个十百千一位的数,且变化得到的每个数也为素数 [解题思路]和poj 3278类似.bfs+queue,分别枚举个十百千的每一位就能够了,只是注意个位仅仅能为奇数,且千位从1開始 代码: #ifndef _GLIBCXX_NO_ASSERT #include <cassert> #endif #include <cctype> #include <cerrno&g…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1973 Prime Path Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Problem Description The ministers of the cabinet were quite upset by the message from the Chief of Secu…
题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1973 Prime Path Description The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-digit room numbers on their offices…
思路:宽度优先搜索(BFS算法) #include<iostream> #include<stdio.h> #include<cmath> #include<cstring> using namespace std; int a,b; struct node{ int num; int step; }; node que[10000];//默认初始化为0 int visit[10000];//默认初始化为0 int prime(int d){ if(d<…
Description The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-digit room numbers on their offices. — It is a matter of security to change such things every now…