[leetcode 字符串处理]Compare Version Numbers @author:wepon @blog:http://blog.csdn.net/u012162613 1.题目 Compare two version numbers version1 and version1. If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0. You may assume…

[LeetCode]165. Compare Version Numbers 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/compare-version-numbers/description/ 题目描述: Compare two version numbers version1 and vers…

Compare Version Numbers Compare two version numbers version1 and version2. If *version1* > *version2* return 1; if *version1* < *version2* return -1;otherwise return 0. You may assume that the version strings are non-empty and contain only digits an…

Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combination. Note: All numbers (including target) will be posi…

Write a program to solve a Sudoku puzzle by filling the empty cells. Empty cells are indicated by the character '.'. You may assume that there will be only one unique solution. A sudoku puzzle... ...and its solution numbers marked in red. 题意分析: 本题是要解…

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 →…

Question 165. Compare Version Numbers Solution 题目大意: 比较版本号大小 思路: 根据逗号将版本号字符串转成数组,再比较每个数的大小 Java实现: public int compareVersion(String version1, String version2) { String[] v1Arr = version1.split("\\."); String[] v2Arr = version2.split("\\.&qu…

Compare Version Numbers 本题收获: 1.字符串型数字转化为整型数字的方法:s[i] - '0',( 将字母转化为数字是[i]-'A'   ) 2.srt.at(),substr(),atoi() 3.字符串型数组的定义:string str[3]={“aaaa”,"bbbb","cccc"};差点跟python混淆了.C++中双引号和单引号的区别. 4.返回值类型要对应 return "0", 5.return 0:的位置…

Compare two version numbers version1 and version2.If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0. You may assume that the version strings are non-empty and contain only digits and the . character.The . characte…

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