03-树3 Tree Traversals Again (25 分)】的更多相关文章

题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/667 5-5 Tree Traversals Again   (25分) An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys n…
1086 Tree Traversals Again (25分)   An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys numbered from 1 to 6) is traversed, the stack operations ar…
7-5 Tree Traversals Again (25 分)   An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys numbered from 1 to 6) is traversed, the stack operations ar…
题意:输入一个正整数N(<=30),接着输入2*N行表示栈的出入(入栈顺序表示了二叉搜索树的先序序列,出栈顺序表示了二叉搜索树的中序序列),输出后序序列. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; stack<int>st; ],b[]; ]; void build(int n,int*a,int*b,int*ans){ if(!n)…
Suppose that all the keys in a binary tree are distinct positive integers. Given the postorder and inorder traversal sequences, you are supposed to output the level order traversal sequence of the corresponding binary tree. Input Specification: Each…
Suppose that all the keys in a binary tree are distinct positive integers. Given the postorder and inorder traversal sequences, you are supposed to output the level order traversal sequence of the corresponding binary tree. Input Specification: Each…
给出一个棵二叉树的后序遍历和中序遍历,求二叉树的层序遍历 #include<bits/stdc++.h> using namespace std; ; int in[N]; int post[N]; typedef struct node; typedef node *tree; struct node { int data; tree L; tree R; }; void print(tree &bt,int l1,int r1,int l2,int r2) { if(l1>r…
An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys numbered from 1 to 6) is traversed, the stack operations are: push(1); push(2); push(3); pop()…
03-树2. Tree Traversals Again (25) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 CHEN, Yue An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with th…
03-树3. Tree Traversals Again (25) 题目来源:http://www.patest.cn/contests/mooc-ds/03-%E6%A0%913 An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys num…
03-树3. Tree Traversals Again (25) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 CHEN, Yue An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with th…
1086. Tree Traversals Again (25) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with th…
题目 An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys numbered from 1 to 6) is traversed, the stack operations are: push(1); push(2); push(3); po…
题意:用栈的push.pop操作给出一棵二叉树的中序遍历顺序,求这棵二叉树的后序遍历. 需要一个堆结构s,一个child变量(表示该节点是其父亲节点的左孩子还是右孩子),父亲节点fa对于push v操作:1).第一个push肯定是根节点root.2).根据child变量,建立fa与v的父子关系.3).由于是中序遍历,所以接下来的节点必定是v的left(如果有的话),child=left,fa=v;4).然后进行push操作 对于pop操作:1).根据中序遍历性质,可知接下来的节点必定是pop节点…
题目如下: An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys numbered from 1 to 6) is traversed, the stack operations are: push(1); push(2); push(3);…
题目描述 Suppose that all the keys in a binary tree are distinct positive integers. Given the postorder and inorder traversal sequences, you are supposed to output the level order traversal sequence of the corresponding binary tree. 给出一个二叉树的后序遍历序列和中序遍历序列…
入栈顺序为先序遍历,出栈顺序为中序遍历. #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<stack> using namespace std; +; const int INF=0x7FFFFFFF; int n,tot; int Preorder[maxn],Inorder[maxn],Postorder[maxn]; int AP…
Source: PAT A1086 Tree Traversals Again (25 分) Description: An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys numbered from 1 to 6) is traversed…
1086. Tree Traversals Again (25) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with th…
1020 Tree Traversals (25 分)   Suppose that all the keys in a binary tree are distinct positive integers. Given the postorder and inorder traversal sequences, you are supposed to output the level order traversal sequence of the corresponding binary tr…
1020 Tree Traversals (25)(25 分) Suppose that all the keys in a binary tree are distinct positive integers. Given the postorder and inorder traversal sequences, you are supposed to output the level order traversal sequence of the corresponding binary…
1020 Tree Traversals (25分)   Suppose that all the keys in a binary tree are distinct positive integers. Given the postorder and inorder traversal sequences, you are supposed to output the level order traversal sequence of the corresponding binary tre…
1020 Tree Traversals (25 分)   Suppose that all the keys in a binary tree are distinct positive integers. Given the postorder and inorder traversal sequences, you are supposed to output the level order traversal sequence of the corresponding binary tr…
题目链接:https://pintia.cn/problem-sets/994805046380707840/problems/994805069361299456 L2-006 树的遍历 (25 分)   给定一棵二叉树的后序遍历和中序遍历,请你输出其层序遍历的序列.这里假设键值都是互不相等的正整数. 输入格式: 输入第一行给出一个正整数N(≤30),是二叉树中结点的个数.第二行给出其后序遍历序列.第三行给出其中序遍历序列.数字间以空格分隔. 输出格式: 在一行中输出该树的层序遍历的序列.数字…
03-树3 Tree Traversals Again(25 point(s)) An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys numbered from 1 to 6) is traversed, the stack operati…
题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/668 5-6 Root of AVL Tree   (25分) An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child subtrees of any node differ by at most one; if at any time they d…
题目地址 https://pta.patest.cn/pta/test/15/exam/4/question/711 5-3 树的同构   (25分) 给定两棵树T1和T2.如果T1可以通过若干次左右孩子互换就变成T2,则我们称两棵树是“同构”的.例如图1给出的两棵树就是同构的,因为我们把其中一棵树的结点A.B.G的左右孩子互换后,就得到另外一棵树.而图2就不是同构的. 图1 图2 现给定两棵树,请你判断它们是否是同构的. 输入格式: 输入给出2棵二叉树树的信息.对于每棵树,首先在一行中给出一个…
1043 Is It a Binary Search Tree (25 分)   A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a…
1021 Deepest Root (25 分)   A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest r…
PAT甲级:1066 Root of AVL Tree (25分) 题干 An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child subtrees of any node differ by at most one; if at any time they differ by more than one, rebalancing is done to rest…